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3 years ago

8

Using logarithm table evaluate the

%5Csqrt%5B4%5D%7B0.007%7D%20%7D%20" id="TexFormula1" title=" \frac{ \sqrt[3 ]{1.376} }{ \sqrt[4]{0.007} } " alt=" \frac{ \sqrt[3 ]{1.376} }{ \sqrt[4]{0.007} } " align="absmiddle" class="latex-formula">

1 answer:

DedPeter [7]3 years ago

4 0

Answer: 3.845312455 just put it in a scientific calculator

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The rate of change of the downward velocity of a falling object is the acceleration of gravity (10 meters/sec 2) minus the accel

Alexus [3.1K]

Answer:

See below

Step-by-step explanation:

Write the initial value problem and the solution for the downward velocity for an object that is dropped (not thrown) from a great height.

if v(t) is the speed at time t after being dropped, v'(t) is the acceleration at time t, so the the initial value problem for the downward velocity is

v'(t) = 10 - 0.1v(t)

v(0) = 0 (since the object is dropped)

<em> The equation v'(t)+0.1v(t)=10 is an ordinary first order differential equation with an integrating factor </em>

$\bf e^{\int {0.1dt}}=e^{0.1t}$

so its general solution is

$\bf v(t)=Ce^{-0.1t}+100$

To find C, we use the initial value v(0)=0, so C=-100

and the solution of the initial value problem is

$\bf \boxed{v(t)=-100e^{-0.1t}+100}$

what is the terminal velocity?

The terminal velocity is

$\bf \lim_{t \to\infty}(-100e^{-0.1t}+100)=100\;mt/sec$

How long before the object reaches 90% of terminal velocity?

90% of terminal velocity = 90 m/sec

we look for a t such that

$\bf -100e^{-0.1t}+100=90\rightarrow -100e^{-0.1t}=-10\rightarrow e^{-0.1t}=0.1\\-0.1t=ln(0.1)\rightarrow t=\frac{ln(0.1)}{-0.1}=23.026\;sec$

How far has it fallen by that time?

The distance traveled after t seconds is given by

$\bf \int_{0}^{t}v(t)dt$

So, the distance traveled after 23.026 seconds is

$\bf \int_{0}^{23.026}(-100e^{-0.1t}+100)dt=-100\int_{0}^{23.026}e^{-0.1t}dt+100\int_{0}^{23.026}dt=\\-100(-e^{-0.1*23.026}/0.1+1/0.1)+100*23.026=1,402.6\;mt$

3 0

3 years ago

How do I do this I'm so confused

suter [353]

Answer:

Pretty sure that x would be positive 37.

Step-by-step explanation:

3 0

2 years ago

Write the symbols for the probability that of all the outfielders, a player is not a great hitter.

Mumz [18]

The symbolic representation of the conditional probability

$P(G'|O) = \frac{P(G'nO)}{P(O)}$

This is a conditional probability problem ; which can be expressed explicitly as ;

The probability of not being a great hitter Given that the player is an outfielder
Recall :

Probability of A given B is defined as ;

$P(A|B) = \frac{P(AnB)}{P(B)}$

Let :

Probability that a player is an outfielders = P(O)

Probability that a player is a Great hitter = P(G)

Probability that a player is not a great hitter = P(G')

Probability that a player is not a great hitter given that he is an outfielder = P(OnG')

Therefore, we have :

$P(G'|O) = \frac{P(G'nO)}{P(O)}$

Learn more : brainly.com/question/18153040

7 0

3 years ago

How to solve I don't know how to go about it

Tems11 [23]

Mathpapa on google ok

7 0

3 years ago

1.67 percent of 20000

Arturiano [62]

Answer:

The answer is 334

Step-by-step explanation:

.0167 x 20000 = 334

3 0

3 years ago