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IrinaK [193]
3 years ago
8

The volume of a rectangular prism can be represented by the expression 216x^3y^2. If the length is 8 y and the width is 9 x , wh

at is the height of the rectangular prism?
2 x^2y
2 x^3y^2
3 x^2y
3 x^3y^2
Mathematics
1 answer:
Nastasia [14]3 years ago
3 0

Answer:

h= 216x^3y^2÷(8yx9X) = 3x^2y

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what is c to the negative 3 power and d to the 5 power over f to the 3 power and g to the negative 7 power
julia-pushkina [17]

Answer:

C^-3+d^5/f^3+g^-7

Step-by-step explanation:

The answer is as seen above

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2 years ago
Factorise x^2 + x - 12
icang [17]

Answer:

(x+4)(x-3)

Step-by-step explanation:

I'm italian. I used a formula that we Italians call "somma e prodotto". Tell me if it's correct.

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3 years ago
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Describe the solution set of compound inequality x&gt;2 or x&lt;7.<br> Please help ❣️<br> o(^o^)o
olganol [36]

If is

x > 2 or x < 7 ⇒ x is any real number

If is

x > 2 and x < 7 ⇒ 2 < x < 7

A set of all numbers that are greater than 2 and less than 7.

Look at the picture.

6 0
4 years ago
Two sides of a triangle are as follows: 2 centimeters and 5 centimeters. Describe the possible lengths of the third side
Elden [556K]

Answer:

3cm < Third side < 7cm

Thus third side can take any value between 3cm and 7 cm

(note: excluding 3 cm and 7 cm)

If the value are integral then possible values of third side are

4cm, 5cm,6cm

Step-by-step explanation:

This question can be solved using given by Triangle Inequality Theorem Given below.

  • Sum of two sides is always greater than value of third side
  • Difference of two sides is always less than value of third side

Given two sides are 2cm, 5cm

Sum of two sides = (2+5)cm = 7 cm

Difference of two sides = (5-2) = 3 cm

Let the third side be X

thus according to Triangle Inequality Theorem

X <  Sum of two sides of given triangle

X < 7cm  -----1

X > Difference of two sides

X > 3cm  ----1

combining expression 1 and 2 we have

3cm < X < 7cm

Thus third side can take any value between 3cm and 7 cm

(note: excluding 3 cm and 7 cm)

If the value are integral then possible values are

4c, 5cm,6c

7 0
3 years ago
IQ scores are measured with a test designed so that the mean is 116 and the standard deviation is 16. Consider the group of IQ s
butalik [34]

Answer:

So the z-scores that separate the unusual IQ scores from those that are​ usual are Z = -2 and Z = 2.

The IQ scores that separate the unusual IQ scores from those that are​ usual are 84 and 148.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 116, \sigma = 16

What are the z scores that separate the unusual IQ scores from those that are​ usual?

If Z<-2 or Z > 2, the IQ score is unusual.

So the z-scores that separate the unusual IQ scores from those that are​ usual are Z = -2 and Z = 2.

What are the IQ scores that separate the unusual IQ scores from those that are​ usual?

Those IQ scores are X when Z = -2 and X when Z = 2. So

Z = -2

Z = \frac{X - \mu}{\sigma}

-2 = \frac{X - 116}{16}

X - 116 = -2*16

X = 84

Z = 2

Z = \frac{X - \mu}{\sigma}

2 = \frac{X - 116}{16}

X - 116 = 2*16

X = 148

The IQ scores that separate the unusual IQ scores from those that are​ usual are 84 and 148.

8 0
3 years ago
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