<span>1. Given a(t) = 90 - 10 log (t + 2) = 75 or
10*log (t + 2) = 90-75 = 15 or log(t+2) = 1.5 or
(t+2) = 10^(1.5) or t = -2+[10*√10] = 29.622 or 29.6 weeks. hence the option, "a.29.6 weeks" is correct.
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The graph of the first plan is a straight line that starts at the origin
and slopes up at the rate of 20¢/minute.
The graph of the second plan starts high up on the y-axis, at the
point where y=$50, and from there it slopes with a very gentle
slope of 2¢/minute.
The slope of the first graph is 10 times as steep as the slope of
the second graph, but they do eventually meet, at x = 278 minutes.
The second plan may seem very expensive, especially since Grace
would need to come up with $50 every month just to keep the phone
working, even before she even uses it. But if she expects to use it
more than 277 minutes in a month ... about 9 to 10 minutes each day,
then that one is actually the cheaper plan, because its minutes are
so much cheaper.
Answer:
If it's hours total, then 20 hours total to fill.
Step-by-step explanation:
If it was filled 5 gallons an hour for 10 hours, 5 times 10=50
So there's 50 gallons out of the 100 gallons filled before the animals drank
If the animals drank 2 gal/h with it still being filled at 5 gal/h FOR 5 HOURS, you subtract the 25 (5 gal/h times 5 hours) by 10 (2 gal/h times 5 hours) to get how much gallons were filled in that time span, which is 15
Since he added a hose that filled at 4 gal/h, you can infer that, in total, it is now 9 gal/h because you add 5+4.
The animals are still going to drink at 2 gal/h, so you subtract 9 from 2 and get 7 gallons filling up the pool per hour.
Since you have 35 gallons left (you already filled 65 gallons), you can divide the 35 by 7 to get 5 hours.
Answer:
slope= -
Step-by-step explanation:
-5--4=-1
6--4=10
Answer:
1. x+(5+7)
2.x+ (8-2)
3. (x+8)
4. x-8
5. 8-x
6. 5-n
7.x+x
8. x+ (8-2)
9. n+5
10. n-5
Step-by-step explanation: