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anastassius [24]
4 years ago
10

A=8 square root of 3 B=16 C=12 D=8

Mathematics
2 answers:
gulaghasi [49]4 years ago
4 0

Step-by-step explanation:

8√383 by √3√333.

8√3⋅√3√383⋅33

Combine and simplify the denominator.

Tap for more steps...

8√33833

The result can be shown in multiple forms.

Exact Form:

8√33833

Decimal Form:

4.61880215

andriy [413]4 years ago
3 0
I believe the answer is B
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Step-by-step explanation:

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3 years ago
F(x)=x^2-3x-2 is shifted 4 units left. The result is g(x) what is g(x)
grandymaker [24]

To solve this problem you must apply the proccedure shown below:

1. If the function f(x)=x^{2}-3x-2 is shifted 4 units left, this means that you must substitute the value of x by x+4 to find g(x), as following:

f(x+4)=(x+4)^{2}-3(x+4)-2

2. Now, expand the function:

f(x+4)=x^{2} +8x+16-3x-12-2\\ f(x+4)=x^{2} +5x+2

3. Then, you have that g(x) is:

g(x)=x^{2} +5x+2

Therefore, the answer is: g(x)=x^{2} +5x+2

3 0
4 years ago
Help me out sophmore math level please please
Masja [62]

Answer:

Lol luckly we both in the same grade working on the same stuff but the answer is 10

Step-by-step explanation:

8x-12... 6x+8

like terms-- 8x-6x & 12+8

                      2x=20

Whats 20 divided by 2

10..!!!!!!

5 0
3 years ago
Two bowls and one cup weigh 800 grams. One bowl and two cups weigh 700 grams. Find the weight of the bowl and the cup
antoniya [11.8K]

Answer:

\large \boxed{\textbf{Bowl = 300 g; cup = 200 g}}  

Step-by-step explanation:

 Let b  = the mass of a bowl  

and c = the mass of a cup  

We have two conditions:  

\begin{array}{lrcl}(1) &2b + c  & = & 800\\(2) & b + 2c & = & 700\\\end{array}

Calculations:  

\begin{array}{lrcll}(3) & 4b + 2c &=  & 1600&\text{ Multiplied (1) by 2}\\& 3b & = & 900&\text{Subtracted (2) from (3)}\\(4) & b & = & \mathbf{300}&\text{Divided each side by 3}\\ & 600 + c & = & 800&\text{Substituted (4) into (2}\\ & c & = & \mathbf{200}\\\end{array}\\\text{The mass of a bowl  is $\large \boxed{\textbf{300 g}}$ and that of a cup is $\large \boxed{\textbf{200 g}}$}

Check:

\begin{array}{rlcrl}2(300) + 200& =800 & & 300 + 2(200) & = 700\\600 + 200 & = 800& & 300 + 400 & = 700\\800 & = 800& & 700 & = 700\\\end{array}

OK.

6 0
3 years ago
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