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2 years ago

(4 times 2 to the third power) - (64 divided by 8)

Mathematics

1 answer:

Irina-Kira [14]2 years ago

7 0

Answer:

Step-by-step explanation:

(4 times 2 to the third power) - (64 divided by 8) = 4*(2^3) - 64/8

= 4*8 - 8 = 32 - 8 = 24

The answer is 24

Hope this helps :)

Have a great day!

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Plz help I need to know how many bags of snacks they bought in all

spin [16.1K]

Answer:

7x - 2

Step-by-step explanation:

let x be the number of bags of chips, then

3x is the number of bags of pretzels ← 3 times the number of bags of chips

3x - 2 is the number of bags of nachos ← 2 less than bags of pretzels

total snacks bought = x + 3x + 3x - 2 = 7x - 2

6 0

3 years ago

A law firm is going to designate associates and partners to a big new case. The daily rate charged to the client for each associ

Semenov [28]

Answer:

$8700

Step-by-step explanation:

Associates cost $800 each, you have 9 associates, so multiply 800 by 9 which gives you: $800x 9= $7200.

Partners cost $1500 each, you have 4 partners, so multiply 1500 by 4 which gives you: $1500x 4=$6000.

Then add the two together like this: $7200+$1500= $8700.

4 0

2 years ago

Read 2 more answers

Express each of these numbers as a product of two fractions: 1

Murrr4er [49]

Your question is incomplete.

5 0

3 years ago

Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x

Serggg [28]

I assume $C$ has counterclockwise orientation when viewed from above.

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

so we first compute the curl:

$\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k$

Then parameterize $S$ by

$\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k$

where the $z$ -component is obtained from

$1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v$

with $0\le u\le\dfrac\pi2$ and $0\le v\le\dfrac\pi2$ .

Take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k$

Then the line integral is equal in value to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}$

6 0

3 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!

zalisa [80]

Answer:

The answe is 2/5m=4

Step-by-step explanation:

If he ate 4 of them, but it means he ate 2/5 muffins,

4 muffins = 2/5 muffins

You substitute x muffins for how much muffins she baked in all -

2/5 * x muffins = 4 or 2/5m = 4

Hope that helped :) <3

5 0

2 years ago