WILL GIVE 100 POINTS AND BRAINLIEST! Prove that the square of the second number out of three consecutive odd numbers is four gre
ater than the product of the first and the third numbers.
2 answers:
Pick 3 consecutive odd numbers:
3, 5, 7
Square the 2nd number: 5 ^ 2 = 25
Multiply the first and 3rd:
3 x 7 = 21
25-21 = 4
This is true.
Try another set of numbers:
9, 11, 13
11^2 = 121
9 x 13 = 117
121-117 = 4
Again it’s true.
Answer:
Let's choose the three odd consecutive numbers 1, 3, and 5.
3^2=9
1•5=5
9-5=4
Let's try the same thing, but with the numbers 101, 103, and 105.
103^2=10609
101•105=10605
10609-10605=4
So, yes, the square of the second number out of three consecutive odd numbers is four greater than the product of the first and the third numbers.
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