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3 years ago

14

X + 25 = 96. Solve for x.

2 answers:

Scorpion4ik [409]3 years ago

8 0

X = 71 because x plus 25 and then u subtract

Jobisdone [24]3 years ago

4 0

Answer:

x = 71

Step-by-step explanation:

x + 25 = 96

=> x = 96 - 25

=> x = 71

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17-2c for c = 7 what is the answer

alexira [117]

Simply substitute the 7 in for c in the equation then solve...

17 - 2c =
17 - 2 (7) =
17 - 14 = 3

7 0

3 years ago

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Limit (sin4x-4sinx)/x^3 when x close to zero

BartSMP [9]

$\Large \boxed{\sf \bf \ \ \lim_{x\rightarrow0} \ {\dfrac{sin(4x)-4sin(x)}{x^3}}=-10 \ \ }$

Step-by-step explanation:

Hello, please consider the following.

Using Maclaurin series expansion, we can find an equivalent of sin(x) in the neighbourhood of 0.

$sin(x) \sim \left(x-\dfrac{x^3}{3!}\right)\\\\\text{So, in the neighbourhood of 0}\\\\\begin{aligned}(sin(4x)-4sin(x)) &\sim \left( 4x-\dfrac{(4x)^3}{3!}-4x+\dfrac{4x^3}{3!}\right)\\\\&\sim \left(\dfrac{x^3*4*(1-4^2)}{3*2}\right)\\\\&\sim \left(\dfrac{x^3*2*(-15)}{3}\right)\\\\&\sim \left(x^3*2*(-5)\right)\\\\&\sim \left(x^3*(-10)\right)\\\end{aligned}$

Then,

$\displaystyle \lim_{x\rightarrow0} \ {\dfrac{sin(4x)-4sin(x)}{x^3}}\\\\= \lim_{x\rightarrow0} \ {\dfrac{-10*x^3}{x^3}}\\\\=-10$

Thank you

4 0

4 years ago

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I need help solving these two equations using substitution!! please helpppp

Levart [38]

Answer:

i would suggest using www.mathpapa.com ^^ its an algebra calculator and saved me in algebra 1

3 0

3 years ago

Ravi drove 871 miles in 13 hours.

professor190 [17]

Answer:11 hours

Step-by-step explanation:

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3 years ago

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Please reference attached image for the problem that requires solving. Thank you so much for taking the time to help.

Lemur [1.5K]

Explanation:

The number of times the 6-sided number cube will be rolled will is

$750$

Let the numbers greater than 4 be represented below as

$E_1$ $\begin{gathered} E_1=\lbrace5,6\rbrace \\ n(E_1)=2 \end{gathered}$

The number of sample space will be

$n(S)=6$

The probability of rolling a number greater than 4 will be calculated below as

$\begin{gathered} Pr(E_1)=\frac{n(E_1)}{n(S)} \\ Pr(E_1)=\frac{2}{6}=\frac{1}{3} \end{gathered}$

Hence,

To calculate the number of times a number greater than 4 will be rolled will be calculated below as

$\begin{gathered} =Pr(E_1)\times750 \\ =\frac{1}{3}\times750 \\ =250times \end{gathered}$

Hence,

The final answer is

$\Rightarrow250\text{ }times$

5 0

1 year ago