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slava [35]
3 years ago
11

Help help help help help please

Mathematics
2 answers:
RideAnS [48]3 years ago
5 0
Angle T: angle H
line UQ: line IE
line RS: FG
sweet-ann [11.9K]3 years ago
5 0

Answer:

angle T -  angle H

line UQ - line IE

line RS -  FG

<h2>If im not wrong :)</h2>

You might be interested in
ASAP!!!!!! show your work plzz!!
Nat2105 [25]
4(p - 7) = 44
First distribute the 4 over the parentheses
4p - 28 = 44
Add 28 to both sides:-
4p = 44 + 28
4p = 72
Divide both sides by 4:-
p = 72/4
p = 18 (answer)
4 0
3 years ago
Worth 17 points! Help me please!!! Look in the picture
ivanzaharov [21]

Answer:

Part A

1. After 4 weeks of work, Jeremy has saved <u>300</u>

2. Jeremy worked <u>8</u> weeks in order to save $600

3. For every one week of work, Jeremy saved <u>75</u> dollars

4. If Jeremy works 15 weeks, then he can expect to save <u>1,125</u> dollars

Part B

1. Saeed orders 15 meals and his total cost of delivery is <u>$24</u>

2. Saeed paid $32 to have <u>20</u> meals delivered

3. For every meal delivered, Saeed is charged <u>$1.6</u>

4. If Saeed pays $19.20 in delivery fees then he ordered <u>12</u> meals

Step-by-step explanation:

Part A

The given graph gives the proportional relationship between total amount saved and the number of weeks worked

1. Reading from the graph, at the point where the vertical line from point 4 touches the line of the graph, an horizontal line to the vertical y-axis touches the y-axis at 300

Therefore;

After 4 weeks of work, Jeremy has saved <u>300</u>

2. The point where an horizontal line from point 600 on the vertical y-axis touches the line of the graph, a vertical line drawn to the horizontal, x-axis touches the x-axis at 8

Therefore;

Jeremy worked <u>8</u> weeks in order to save $600.

3. The rate of change of the amount saved to the number of weeks worked, 'm', for the given proportional relationship (straight line relationship, passing through the origin) is given as follows;

Rate of change, m = Constant = y/x

∴ Rate of change of the amount saved to the number of weeks worked = (300-0)/(4 weeks- 0 week) = 75/week

Therefore;

For every one week of work, Jeremy saved <u>75</u> dollars

4. The amount Jeremy would have saved in 15 weeks, 'A', is given as follows;

A = m × n

Where;

m = The rate of change of the amount saved to the number of weeks worked = 75/week

n = The number of weeks worked

∴ A = 75/week × 15 = $1,125

Therefore;

If Jeremy works 15 weeks, then he can expect to save <u>1,125</u> dollars

Part B

From the graph, we have;

1. From the graph there is a proportional relationship between the total cost of delivery and the number of meals

At the point a vertical line drawn to the line of the graph from 15 on the horizontal axis (number of meals), a horizontal line drawn to the vertical y-axis touches the y-axis at 24

Therefore;

1. Saeed orders 15 meals and his total cost of delivery is <u>$24</u>

2. From the point where the horizontal line from 32 on the vertical axis touches the linear graph of the relationship between the total cost of delivery and the number of meals, a vertical line drawn down to the horizonal axis touches the horizontal x-axis at 20

Therefore;

Saeed paid $32 to have <u>20</u> meals delivered

3. The rate of change of the total cost of delivery to the number of meals, 'm', is given as follows;

m = y/x (for proportional relationships)

Taking any corresponding 'x' and y-values

m = 16/10 = 32/20 = 24/15 = 1.6 Dollars/meal

Therefore;

For every meal delivered, Saeed is charged <u>$1.6</u>

4. From m = y/x = 1.6

When y = $19.20

x = y/m = $19.20/($1.6/meal) = 12 meals

Therefore;

If Saeed pays $19.20 in delivery fees then he ordered <u>12</u> meals.

3 0
3 years ago
When simplifying an exponential expression what happens to an exponent when it is moved from the numerator to the denominator or
Gala2k [10]

Answer:

Hi I don't really get it but I'll do my best to figure it out.

Basically if a numerator has a negative exponent it would be moved to the bottom to make the exponent positive.

IF there is a negative exponent at the denominator  you move it to the top to make it positive.

Hope that helps.

3 0
3 years ago
What is the first derivative of r with respect to t (i.e., differentiate r with respect to t)? r = 5/(t2)Note: Use ^ to show exp
adelina 88 [10]

Answer:

The first derivative of r(t) = 5\cdot t^{-2} (r(t)=5*t^{-2}) with respect to t is r'(t) = -10\cdot t^{-3} (r'(t) = -10*t^{-3}).

Step-by-step explanation:

Let be r(t) = \frac{5}{t^{2}}, which can be rewritten as r(t) = 5\cdot t^{-2}. The rule of differentiation for a potential function multiplied by a constant is:

\frac{d}{dt}(c \cdot t^{n}) = n\cdot c \cdot t^{n-1}, \forall \,n\neq 0

Then,

r'(t) = (-2)\cdot 5\cdot t^{-3}

r'(t) = -10\cdot t^{-3} (r'(t) = -10*t^{-3})

The first derivative of r(t) = 5\cdot t^{-2} (r(t)=5*t^{-2}) with respect to t is r'(t) = -10\cdot t^{-3} (r'(t) = -10*t^{-3}).

5 0
3 years ago
The train station of new york city and burlington, vermont, are approximately 295 miles apart. One train leaves new york for bur
n200080 [17]

Answer:

8:04 am

Step-by-step explanation:

The first train travels 60 miles from 6am to 7am

So at 7am the trains are 455 - 60 = 395 miles apart

First train: Distance from town A (DA) = Velocity* time = 60t

Second train: Distance from town B (DB) = Velocity*time = 70t

So, DA + DB = 60t + 70t

395 = 130t

t = 395/130

= 3.4 hrs

= 3 hrs 4 mins

The first train left at 5am so the exact time would be 8:04am (5am +3 hrs and 4 minutes)

6 0
3 years ago
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