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3 years ago

Help help help help help please

Mathematics

2 answers:

RideAnS [48]3 years ago

5 0

Angle T: angle H
line UQ: line IE
line RS: FG

sweet-ann [11.9K]3 years ago

5 0

Answer:

angle T - angle H

line UQ - line IE

line RS - FG

<h2>If im not wrong :)</h2>

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The cost of a large pizza is given by c = 0.50t + 18, where c is the total cost and t is the number of toppings. The cost of a m

Mashutka [201]

The toppings would still cost 0.50 each (since it is just toppings)

The large pizza costs $18 if you do not have any toppings
The medium costs half of the large

18/2 = 9

The medium costs $9 without any toppings, so your new equation will be:

c = 0.50t + 9

hope this helps

6 0

3 years ago

Read 2 more answers

Please show your work

Effectus [21]

Here hope this help the solution is X= -2 and y=9

4 0

2 years ago

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$