23.50 is rounded to nearest hundredth
SOLUTION:
PQR is a right-angle triangle.
Therefore, to solve this problem, we will use Pythagoras theorem which is only applicable to right-angle triangles.
Pythagoras theorem is as displayed below:
a^2 + b^2 = c^2
Where c = hypotenuse of right-angle triangle
Where a and b = other two sides of right-angle triangle
Now we will simply substitute the values from the problem into Pythagoras theorem in order to obtain the length of QR.
c = PQ = 16cm
a = PR = 8cm
b = QR = ?
a^2 + b^2 = c^2
( 8 )^2 + b^2 = ( 16 )^2
64 + b^2 = 256
b^2 = 256 - 64
b^2 = 192
b = square root of ( 192 )
b = 13.8564...
b = 13.86 ( to 2 decimal places )
FINAL ANSWER:
Therefore, the length of QR is 13.86 centimetres to 2 decimal places.
Hope this helps! :)
Have a lovely day! <3
Answer: 1/17
Step-by-step explanation: The denominator gets larger by 3 each time. That's it!
17
>
12
Which statement best describes this inequality when graphed on a number line where positive numbers are to the right of zero?
12 is located to the right of 17.
12 is located to the right of 17.
17 is located to the right of 12.
17 is located to the right of 12.
12 is located 12 units to the left of zero, and 17 is located 17 units to the right of zero.
12 is located 12 units to the left of zero, and 17 is located 17 units to the right of zero.
17 is located 17 units to the left of zero, and 12 is located 12 units to the right of zero.
Can I get the measures of the figures? I’d be glad to help :))