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Yuri [45]
3 years ago
12

Help me out in this question please

Mathematics
2 answers:
bulgar [2K]3 years ago
6 0
It’s D cuz I used calculator heheh
QveST [7]3 years ago
5 0

Answer:

The Answer is D, 6 1/12

Step-by-step explanation:

1. 3 1/4 = 3 3/12

2. 2 5/6 = 2 10/12

3. 3 3/12 + 2 10/ 12 = 5 13/12

4. 5 13/12 = 6 1/12

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How do you find the value of √a⁴ ??<br> (ill give brainliest)
dsp73

Answer:

a^{2}

Step-by-step explanation:

√a^4 is the same as:

√a × √a × √a × √a

group them as 2 pairs of

(√a × √a) × (√a × √a)

which makes

a × a

which is the same as a^{2}

5 0
3 years ago
This is a 3 part 1 question each part on how to locate the plane and a small explanation report working out the recovery details
sesenic [268]

Third leg.

The crew flies at a speed of 560 mi/h in direction N-20°-E.

The wind has a speed of 35 mi/h and a direction S-10°-E.

We then can draw this as:

We have to add the two vectors to find the actual speed and direction.

We will start by adding the x-coordinate (W-E axis):

\begin{gathered} x=560\cdot\sin (20\degree)+35\cdot\sin (10\degree) \\ x\approx560\cdot0.342+35\cdot0.174 \\ x\approx191.53+6.08 \\ x\approx197.61 \end{gathered}

and the y-coordinate (S-N axis) is:

\begin{gathered} y=560\cdot\cos (20\degree)-35\cdot\cos (10\degree) \\ y\approx560\cdot0.940-35\cdot0.985 \\ y\approx526.23-34.47 \\ y\approx491.76 \end{gathered}

Then, the actual speed vector is v3=(197.61, 491.76).

The starting location for the third leg is R2=(216.66, 167.67) [taken from the previous answer].

Then, we have to calculate the displacement in 20 minutes using the actual speed vector.

We can calculate the movement in each of the axis. For the x-axis:

\begin{gathered} R_{3x}=R_{2x}+v_{3x}\cdot t \\ R_{3x}=216.66+197.61\cdot\frac{1}{3} \\ R_{3x}=216.66+65.87 \\ R_{3x}=282.53 \end{gathered}

NOTE: 20 minutes represents 1/3 of an hour.

We can do the same with the y-coordinate:

\begin{gathered} R_{3y}=R_{2y}+v_{3y}\cdot t \\ R_{3y}=167.67+491.76\cdot\frac{1}{3} \\ R_{3y}=167.67+163.92 \\ R_{3y}=331.59 \end{gathered}

The final position is R3 = (282.53, 331.59).

To find the distance from the origin and direction, we transform the cartesian coordinates of R3 into polar coordinates:

The distance can be calculated as if it was a right triangle:

\begin{gathered} d^2=x^2+y^2_{} \\ d^2=282.53^2+331.59^2 \\ d^2=79823.20+109951.93 \\ d^2=189775.13 \\ d=\sqrt[]{189775.13} \\ d\approx435.63 \end{gathered}

The angle, from E to N, can be calculated as:

\begin{gathered} \tan (\alpha)=\frac{y}{x} \\ \tan (\alpha)=\frac{331.59}{282.53} \\ \tan (\alpha)\approx1.1736 \\ \alpha=\arctan (1.1736) \\ \alpha=49.56\degree \end{gathered}

If we want to express it from N to E, we substract the angle from 90°:

\beta=90\degree-\alpha=90-49.56=40.44\degree

Answer: the final location can be represented with the vector (282.53, 331.59).

1) The distance from the origin is 435.63 miles and

2) the direction is N-40°-E.

7 0
10 months ago
Please help I'm almost out of time ​
Serhud [2]

Answer:

3/2

Step-by-step explanation:

move the 3x to the other side and divide it by 2

3 0
2 years ago
From where Kiana is standing, she must look up at a 50° angle to see the top of a building. If she backs up 50 feet, she will ne
Morgarella [4.7K]
For this case, what we must do is solve the following system of equations:
 tan (50) = h / x
 tan (40) = h / (x + 50)
 Solving the system we have:
 (x + 50) * tan (40) = h
 (x) * tan (50) = h
 Matching:
 (x + 50) * tan (40) = (x) * tan (50)
 Rewriting:
 x (tan (50) - tan (40)) = 50 * tan (40)
 x = 50 * tan (40) / (tan (50) - tan (40))
 x = 118.9692621
 Substituting:
 h = (x) * tan (50)
 h = (118.9692621) * tan (50)
 h = 141.7820455
 Answer:
 
The height of the building is:
 
h = 141.7820455 ft
5 0
2 years ago
Read 2 more answers
-12+8d &lt;52 <br> Please answer
Radda [10]

Answer:

d < 8

Step-by-step explanation:

Given

- 12 + 8d < 52 ( add 12 to both sides )

8d < 64 ( divide both sides by 8 )

d < 8

6 0
3 years ago
Read 2 more answers
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