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kodGreya [7K]
3 years ago
12

HELP solve for x. -2x-5-4= x=

Mathematics
1 answer:
stepladder [879]3 years ago
7 0

Answer:

X= -3

(hopefully this helps)

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What is the slope of this ​
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Answer:

Step-by-step explanation:

x = (0.5,0)

y= (0,-3)

slope = 2

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2 + 3(x + 2x) = −2x(2 − 4) + 1<br><br> A) −5 <br> B) −<br> 1<br> 5<br> C) 5 <br> D) <br> 1<br> 5
11Alexandr11 [23.1K]

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B -1/5

you have to follow pemdas first get rid of the parethase which leaves you with 2+3x+6x=-4x+8x+1 then you add what you can do then you get 2+9x=4x+1 then you subtract 2 from both sides and subtract 4x from both sides which leaves you with 5x=-1 then you divide 5 from both sides and get x=-1/5

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HELP ME PLEASE!
Amiraneli [1.4K]
(1.2×10^-3)/(4×10^6)
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3 years ago
Place the samples in order from the sample with the greatest variation to the sample with the least variation.
yulyashka [42]
60 women, 45 women, 20 women, 5women ,
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In isosceles $\triangle abc$ (with $ab = ac$), point $d$ lies on $ab$ such that $cd = cb$. if $\angle adc = 115^\circ$, what is
Nuetrik [128]

1. Angles ADC and CDB are supplementary, thus

m∠ADC+m∠CDB=180°.

Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.

2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then

m∠CDB=m∠CBD=65°.

The sum of the measures of interior angles of triangle is 180°, therefore,

m∠CDB+m∠CBD+m∠BCD=180° and

m∠BCD=180°-65°-65°=50°.

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m∠ABC=m∠ACB.

From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So

m∠ACB=65°.

4. Angles BCD and DCA together form angle ACB. This gives you

m∠ACB=m∠ACD+m∠BCD,

m∠ACD=65°-50°=15°.

Answer: 15°.

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