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3 years ago

Point P′(−3, 2) is the image of point

Mathematics

1 answer:

vampirchik [111]3 years ago

5 0

Answer:

The image of (0, -6) after the same transformation is (-6, -12)

Step-by-step explanation:

After the required translation, the given image of the given point P(3, 8) is P'(-3, 2)

Therefore, the translation of preimage P(3, 8) to the image P'(-3, 2) is given by the difference between the coordinates as follows;

The translation from P(3, 8) to P'(-3, 2) = T(-3 - 3, 2 - 8) = T(-6, -6)

Therefore after the same translation, the preimage of (0, -6) will have an image given as follows;

Coordinate of preimage (0, -6) → T(-6, -6) (0, -6) = (0+ -6, -6 + -6) → Coordinate of image (-6, -12)

The image of (0, -6) after the same transformation = (-6, -12).

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MAXImum [283]

Answer:

Step-by-step explanation:

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3 years ago

Austin correctly answered 92% of the questions on a geography quiz. Liz answered 47 of the 50 questions correctly. Who earned th

Llana [10]

Liz scored higher.

Step-by-step explanation:

Given,

Correct answers by Austin = 92%

Total questions = 50

Correctly answered by Liz = 47

Percent of Liz's correct answers = $\frac{Correct\ answers}{Total\ questions}*100$

Percent of Liz's correct answers = $\frac{47}{50}*100$

Percent of Liz's correct answers = $\frac{4700}{50} = 94\%$

As 94% is higher than 92%, therefore;

Liz scored higher.

Keywords: percent, division

Learn more about division at:

#LearnwithBrainly

3 0

3 years ago

Classify ABC by its sides. Then determine whether it is a right triangle.

m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

$AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

AB = $\sqrt{(9-3)^{2}+(6-3)^{2} } = \sqrt{6^{2}+3^{2} } =\sqrt{45}$

Given vertices are B(6,9) and C( 6,-3)

$B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

= $\sqrt{(-3-9)^{2}+(6-6)^{2} } =\sqrt{12^{2} } = 12$

BC = 12

Given vertices are A(3,3) and C( 6,-3)

$AC = \sqrt{(6-3)^{2}+(-3-3)^{2} } = \sqrt{9+36} = \sqrt{45}$

AC² = AB²+BC²

45 = 45+144

45 ≠ 189

∴Given Δ ABC is not a right angle triangle

5 0

3 years ago

What is the interest on 3000 at a rate of 0.04 for 3 years

xxMikexx [17]

Basically what you need to do is:
3000 X 0.04^3
I would give an answer but I don’t have a calculator at the moment, but I hope this helps

8 0

3 years ago

Missy’s rotation maps point k (17,-12)to k (12,17) which describes the rotation?

Dennis_Churaev [7]

Answer:

This would be a 90 degree rotation in a counter clockwise fashion.

Step-by-step explanation:

You can tell this because in a 90 degree shift, the values switch terms. Also, one of the terms will change the sign.

4 0

3 years ago

Read 2 more answers