<h3>
Answer: 144</h3><h3>
Step-by-step explanation:</h3><h3 />
Since, the first 9 multiple of 4 starts from 0 are,
0, 4, 8, 12, 16, 20, ................
Which is an AP,
Having the first term, 
And, the successive difference, d = 4,
Since, the sum of the n term of an AP,
![S_n = \frac{n}{2}[2a + (n-1)d]](https://tex.z-dn.net/?f=S_n%20%3D%20%5Cfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n-1%29d%5D)
Hence the sum of 9 term of the above AP,
![S_9 = \frac{9}{2}[2\times 0 + (9-1)\times 4]](https://tex.z-dn.net/?f=S_9%20%3D%20%5Cfrac%7B9%7D%7B2%7D%5B2%5Ctimes%200%20%2B%20%289-1%29%5Ctimes%204%5D)
Answer:5
Step-by-step explanation: the like moves at and angle bc u started going faster due to running
Answer:
That's not math.....that's what appears to be Chemistry.
Step-by-step explanation:
I don't see a question....
Answer:
(9, 6)
Step-by-step explanation:
<u>Midpoint formula is:</u>
- x = (x₁ + x₂)/2
- y = (y₁ + y₂)/2
<u>Having coordinates of one end- and midpoint </u>(-5, 12) <u>and</u> (2, 9)<u>:</u>
- x₁ = -5, y₁ = 12
- x = 2, y = 9
<u>we get the coordinates of the missing endpoint with coordinates</u> (x₂, y₂):
- x₂ = 2x - x₁ = 2*2 - (-5) = 4 + 5 = 9
- y₂ = 2y - y₁ = 2*9 - 12 = 18 - 12 = 6
<u>So the missing point is</u>: (9, 6)
Answer: 3.61×10^5 A
Step-by-step explanation: Since the brain has been modeled as a current carrying loop, we use the formulae for the magnetic field on a current carrying loop to get the current on the hemisphere of the brain.
The formulae is given below as
B = u×Ia²/2(x²+a²)^3/2
Where B = strength of magnetic field on the axis of a circular loop = 4.15T
u = permeability of free space = 1.256×10^-6 mkg/s²A²
I = current on loop =?
a = radius of loop.
Radius of loop is gotten as shown... Radius = diameter /2, but diameter = 65mm hence radius = 32.5mm = 32.5×10^-3 m = 3.25×10^-2m
x = distance of the sensor away from center of loop = 2.10 cm = 0.021m
By substituting the parameters into the formulae, we have that
4.15 = 1.256×10^-6 × I × (3.25×10^-2)²/2{(0.021²) + (3.25×10^-2)²}^3/2
4.15 = 13.2665 × 10^-10 × I/ 2( 0.00149725)^3/2
4.15 = 1.32665 ×10^-9 × I / 2( 0.000058)
4.15 × 2( 0.000058) = 1.32665 ×10^-9 × I
I = 4.15 × 2( 0.000058)/ 1.32665 ×10^-9
I = 4.80×10^-4 / 1.32665 ×10^-9
I = 3.61×10^5 A
