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3 years ago

What is an equation of the line that passes through the points (1,4) and (-2,-8)?

Mathematics

1 answer:

natita [175]3 years ago

8 0

Answer: I know it 4 but I don’t know the equation for it, I can only help you this far.(hope it help)

Step-by-step explanation:

(1,4) and (-2,-8)

(x is the first number of the point which is 1 and -2, y is the second number of the point which is 4 and -8.)

(x1 is 1, it alway the first point they tell you on the problem like (1,-4) is on the problem first so it gonna be x1 and y1, for x2 it -2, it alway the second point in the problem like (-2,-8) is the second point they tell you so it gonna be y1 and y2.)

Do x2 - x1 and y2 - y1(y/x)

-8 - 4/-2 - 1 = -12/-3

-12/-3 divide top and bottom by -3, that would equal to 4

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The answer for this is less than 887

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3 years ago

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What is the length 52 ft the width is 9 ft

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Assuming you're asking for the area and the length is 52 ft...

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3 years ago

A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha

White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

$\frac{dB}{dt} = rB-k$

$\Rightarrow \frac{dB}{dt} - rB=-k$ .......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor $=e^{\int p(t) dt$

$=e^{\int (-r)dt$

$=e^{-rt}$

Multiplying the integrating factor the both sides of equation (1)

$e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}$

$\Rightarrow e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt$

Integrating both sides

$\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt$

$\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C$ [ where C arbitrary constant]

$\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}$

Initial condition B=7864 when t =0

$\therefore 7864= \frac{k}{r} - Ce^0$

$\Rightarrow C= \frac{k}{r} -7864$

Then the general solution is

$B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}$

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

$B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}$

$\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0$

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

=$1573.17

4 0

4 years ago

A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer

pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

$Z_{o.o5}$ = -1.648

You reverse the standardization using the formula $Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)$

$-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }$

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

$Z_{0.95}= 1.648$

$1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }$

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

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3 years ago

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Find the values of the variables in the parallelogram. The diagram is not to scale.

Anna [14]

Answer:

Option C

Step-by-step explanation:

x = 36° as alternate interior angles are congruent
z = 110° as opposite angles of parallelogram are congruent
x + y + 110° = 180° as adjacent angles of parallelogram are supplementary
y = 180° - 110° - 36° = 34°

Correct choice is C

8 0

2 years ago