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3 years ago

Use the figure to find the measures of the numbered angles. EXPLAIN YOUR REASONING

Mathematics

2 answers:

jek_recluse [69]3 years ago

8 0

6 is 61
5 and 7 are 119 (180 - 61)
4 and 2 are 61
1 and 3 are 119

Korvikt [17]3 years ago

3 0

Answer:

1 = 61°

2 = 119°

3 = 61°

4 = 119°

5 = 119°

6 = 61°

7 = 119°

Step-by-step explanation:

∠1 and 61° are corresponding angles, therefore, they would be the same angle; ∠1 = 61°.

∠2 and 61° are supplementary angles, therefore, ∠2 would be 119°.

∠3 and ∠1 are vertical angles, therefore, ∠3 = 61°.

∠4 and ∠3 are supplementary angles, therefore, ∠4 would be 119°.

∠5 and 61° are supplementary angles, therefore, ∠5 would be 119°.

∠6 and ∠1 are alternate exterior angles, therefore, ∠6 would be 61°.

∠7 and ∠6 are supplementary angles, therefore, ∠7 would be 119°.

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A student concluded that the inequality −3+2y≤4x is equivalent to the inequality y≥2x+32, as shown below. Describe and correct t

timofeeve [1]

Answer:

$-3 +2y \leq 4x$

$2y \leq 4x+3$

$y \leq 2x + \frac{3}{2}$

And that's different from the claim of the student that:

$y \geq 2x +\frac{3}{2}$

The error of the student is that he/she changes the sign of the inequality from $\leq$ to $\geq$ and that's not possible since we don't multiply both sides of the equation by -1

Step-by-step explanation:

For this case we have the following inequality:

$-3 +2y \leq 4x$

We want to rewrite the last expression with y in the left and x in the right so we can begin adding 3 in both sides of the inequality and we got:

$2y \leq 4x+3$

Now we can divide both sides of the inequality by 2 and we got:

$y \leq 2x + \frac{3}{2}$

And that's different from the claim of the student that:

$y \geq 2x +\frac{3}{2}$

The error of the student is that he/she changes the sign of the inequality from $\leq$ to $\geq$ and that's not possible since we don't multiply both sides of the equation by -1

5 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST!

svetoff [14.1K]

Answer:

x=4.5 or 9/2

Step-by-step explanation:

$\frac{6}{3}$ = $\frac{9}{x}$