Answer: The temperature of the gas if 65.85g of N2 are placed in 17.5L container with a pressure of 1988 mmHg is 1780. 6° C
Explanation:
The ideal gas law states that the volume, pressure and temperature of the a gas is related to the number of moles.
It is represented thus;
P V = n R T
Parameters :
Pressure, P = 1988 mmHg
Volume, V = 17.5 L
number of moles, n = mass ÷ molar mass
mass of N2 = 65.84g
Molar mass of N2 = 28.02 g/ mol
n = 65.85 ÷ 28.02
n = 2. 350 moles.
Temperature = ?
Universal gas constant, R = 8.314 J/mol. K
Calculations :
T = P V ÷ n R
T = 1988 × 17.5 ÷ 2.350 × 8.314
T = 34790 ÷ 19. 5379
T = 1780. 6 ° C
Thus, the temperature of the gas is 1780. 6 ° C
Answer is: mass of water is 56.28 grams.
Chemical reaction: 2H₂O → 2H₂ + O₂.
m(O₂) = 50.00 g.
n(O₂) = m(O₂) ÷ M(O₂).
n(O₂) = 50 g ÷ 32 g/mol.
n(O₂) = 1.5625 mol.
From chemical reaction: n(O₂) : n(H₂O) = 1 : 2.
n(H₂O) = 2 · 1.5625 mol.
n(H₂O) = 3.125 mol.
m(H₂O) = n(H₂O) · M(H₂O).
m(H₂O) = 3.125 mol · 18.01 g/mol.
m(H₂O) = 56.28 g.
B - The reactants are the starting substances and the products are the end substances.
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