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383.5 grams is the mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution.
Explanation:
Given that:
Solution to be prepared is 5.5 %
mass of KCl is 22 gram
mass of water required =?
5.5 % solution means that
5.5 grams in 100 ml or gram of water to make solution.
let the water required is 5.5 + x, so the equation will be
5.5 = x 100
121+ 5.5x = 2200
5.5 x = 2200-121
x =
x = 378 grams
The mass of water added to KCl to make it 5.5% percent solution is
5.5 +378
= 383.5 grams.
to make the solution of 5.5 percent of KCl weighing 22 grams.