Answer:
AFAIK
Explanation:
uric acid is much less toxic than ammonia, hence bigger concentrations of it are tolerated in the body. This means you can excrete it while excreting very little water - beneficial wherever water's not abundant.
There's a tradeoff though, uric acid requires more energy to synthesize than ammonia, so pretty much all fish, say, excrete ammonia rather than uric acid - it's no problem to dilute ammonia since there's no water shortage.
Answer:
1.16atm
Explanation:
We are going to derive the mass of ether from density
mass=density *volume
Also moles=mass/molecular mass
molar mass C2H5OC2H5 =74.12 g/mole
the density of ether is 0.7134 g/ml
mass C2H5OC2H5 = 5.30 ml x 0.7134 g/ml = 3.78 g
moles C2H5OC2H5 =3.78 g x 1 mole/74.12 g = 0.0509 moles
PV = nRT where P=?; n=0.0509 moles; V=6.50L; R=0.0821 Latm/Kmol; T=35ºC +273 = 308K
P = nRT/V = 0.0509)(0.0821)(308)/6.50
P = 0.198 atm (to 3 significant figures (this is the partial pressure of diethyl ether).
TOTAL PRESSURE
P1+p2+p3
= 0.198 atm + 0.750 atm + 0.207 atm =1.1550atm
1.16atm(3 significant figures)
Answer:
Final temperature of water is 
Explanation:
1 mol of LiBr releases 48.83 kJ of heat upon dissolution in water.
So, 2 moles of LiBr release 
or 97.66 kJ of heat upon dissolution in water.
This amount of heat is consumed by 1000.0 g of water. Hence temperature of water will increase.
Let's say final temperature of water is 
.
So, change in temperature (
) of water is 
or (t-25) K
Heat capacity (C) of water is 
Hence, 
where m is mass
So, 
or, 
Hence final temperature of water is
The intellectual and practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment.
Answer:
17.689g
Explanation:
1: First, write out the equation you will follow:
Ca + S ⇒ CaS
2: Use the formula Mass = Mr x moles to work out the moles of both Ca and S - this will enable you to find the limiting reactant.
3: Moles Ca:
Moles = mass/ Mr = 15.3/ 40.1 = 0.382 moles.
4: Moles S:
Moles = mass/ Mr = 7.96/ 32.1 = 0.245 moles.
5: We now know S is the limiting reactant, and as there is a 1:1 ratio between S and CaS, there will also be 0.245 moles CaS.
6: Mass CaS:
Mass = Mr x moles = 72.2 x 0.245 = 17.689g
