The answer is x=16
complimentary means that when the measures of both angles are added together they equal 90 degrees. To get the answer you subtract 48 from 90 and get 42. Then you subtract 10 from 42 because it is added in the parentheses. Then you divide 32 by 2 and you get your answer which is 16.
Y axis is counting by 2's
it started at 2 and went up to 6
Y = 4
X axis is counting by 2'2
starts at one goes to 3
X = 2
Slope is 4/2 because rise over run
4/2 = 2
Slope is simplified to 2.
Answer: (3a + 1) (a + 3)
Step-by-step explanation:
<u>Concept:</u>
Here, we need to know the idea of factorization.
It is like "splitting" an expression into a multiplication of simpler expressions. Factoring is also the opposite of Expanding.
<u>Solve:</u>
Given = 3a² + 10a + 3
<em>STEP ONE: separate 3a² into two terms</em>
3a
a
<em>STEP TWO: separate 3 into two terms</em>
3
1
<em>STEP THREE: match the four terms in ways that when doing cross-multiplication, the result will give us 10a.</em>
3a 1
a 3
When cross multiply, 3a × 3 + 1 × a = 10a
<em>STEP FOUR: combine the expression horizontally to get the final factorized expression.</em>
3a ⇒ 1
a ⇒ 3
(3a + 1) (a + 3)
Hope this helps!! :)
Please let me know if you have any questions
Given:

x lies in the III quadrant.
To find:
The values of
.
Solution:
It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.
We know that,




x lies in the III quadrant. So,


Now,



And,





We know that,



Therefore, the required values are
.