You can use the similarity approach of these two triangles CBD and CAE
as a result:
so:
? = 6x^2 / 10 = 0.6 x^2
and the fact of:
"The
segment connecting the midpoints of two sides of a triangle is parallel to the
third side and equals its half length"
so:BD = 0.5 AE 10 = 0.5 * 2x >>> x= 10
Back to:
? =0.6 x^2 = 0.6 * 10^2 = 0.6 * 100 = 60
AHope that helps
A. x intercepts are where the graph hits the x axis or where f(x)=0
0=2x^2-x-10
solve
hmm
we can use the ac method
multiply 2 and -10 to get -20
what 2 numbers muliply to get -20 and add to get -1 (the coefint of the x term)
-5 and 4
split the midd into that
0=2x^2+4x-5x-10
group
0=(2x^2+4x)+(-5x-10)
factor
0=2x(x+2)-5(x+2)
undistribute
0=(x+2)(2x-5)
set each to 0
0=x+2
0=-2
0=2x-5
5=2x
5/2=x
x intercepts are at x=-2 and 5/2 or the points (-2,0) and (5/2,0)
B. ok, so for f(x)=ax^2+bx+c
if a>0, then the parabola opens up and the vertex is a minimum
if a<0 then the parabola opens down and the vertex is a max
f(x)=2x^2-x-10
2>0
opoens up
vertex is minimum
ok, the vertex
the x value of the vertex in f(x)=ax^2+bx+c= is -b/(2a)
the y value of the vertex is f(-b/(2a)) so
given
f(x)=2x^2-x-10
a=2
b=-1
-b/2a=-(-1)/(2*2)=1/4
f(1/4)=2(1/4)^2-(1/4)-10
f(1/4)=2(1/16)-1/4-10
f(1/4)=1/8-1/4-10
f(1/4)=1/8-2/8-80/8
f(1/4)=-81/8
so the vertex is (1/4,-81/8) or (0.25,-10.125)
C. graph the x intercepts and the vertex
the vertex is min and the graph goes through the x intercepts
C) 84
7(6x2)
Sry if it’s wrong
Answer:
All real numbers
Step-by-step explanation:
The domain represents the x-coordinates, so you can see on the graph that it goes all the way out to both the left and right directions, meaning it covers all the negative numbers, and all the positive numbers. The question is trying to trick you into thinking about the range, but forget about the y-axis for this one.
Answer:
Answer is b
Step-by-step explanation:
just did it
