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saw5 [17]
3 years ago
11

Please help me solve for x

Mathematics
1 answer:
Masja [62]3 years ago
4 0
-99 for answer for xxxxxxxxxxxxxxxxxxxxxxxxxxx
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The amount that results when $3,000 is compounded at 7% annually over eight years. 1792.44 4680 5154.56
jeka57 [31]
I=prt. I=3,000x.07x8. I=210x8. I=1,680. 3,000+1,680=4,680 :)
4 0
3 years ago
Area of a triangle base 2 1/2 height 4 1/6
Lera25 [3.4K]

Answer:

5.21

Step-by-step explanation:

4 1/6 times 4.5 = 10.42 but since it is a triangle you divide by 2 and get 5.21

5 0
3 years ago
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a type of bacteria in a petri dish doubles every hour. If there were 1073741824 bacteria after 24 hours, how many where there to
ArbitrLikvidat [17]

Answer:

yes

Step-by-step explanation:

3 0
4 years ago
An expandable cone-shaped funnel consists of two sections as shown. ( Question A) What is the volume of the bottom section? ( Qu
vitfil [10]

Image of the cone is attached.

Answer:

a) 24π cm³

b) 168π cm³

Step-by-step explanation:

We know the formula for volume of a cone is expressed as:

V = \frac{1}{3} \pi r^2 h

a) To find the volume of the bottom section, given the values:

diameter, d = 6 cm

radius, r = \frac{d}{2} = \frac{6}{2}= 3 cm

height, h = 8cm

Let's use the formula,

V = \frac{1}{3} \pi r^2 h

Substituting values, we have:

V = \frac{1}{3} \pi 3^2 * 8

Vtop = 24π cm³

Therefore, volume of the bottom section of the cone is 24π cm³

b) volume of the top section.

Volume of the top section would be derived by subtracting the volume of the bottom section from the volume of the cone.

Vtop = V - Vbottom

Now, let's find the volume of the cone.

Given:

diameter, d = 12 cm

radius, r = \frac{d}{2} = \frac{12}{2}= 6 cm

height, h = 16cm

Let's use the formula,

V = \frac{1}{3} \pi r^2 h

Substituting values, we have:

V = \frac{1}{3} \pi 6^2 * 16

V = 196π cm³

Therefore, volume of the bottom section =

Vtop = V - Vbottom

= 192π - 24π

= 168π cm³

Therefore volume of the top section of the cone is 168π cm³

4 0
3 years ago
Read 2 more answers
Im doing combining like terms with rational coefficients and i have a problem that says 11/12 - 1/6q + 5/6q - 1/3
WINSTONCH [101]
= 11/12 - 1/6q + 5/6q - 1/3
to add like terms, we must first convert 1/3 to a common denominator with 11/12

= 11/12 - 1/6q + 5/6q - 4/12
combine like terms

= (-1/6q + 5/6q) + (11/12 - 4/12)
add/subtract inside each parentheses

= 4/6q + 7/12
simplify 4/6 by 2

= 2/3q + 7/12


ANSWER: 2/3q + 7/12

Hope this helps! :)
7 0
4 years ago
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