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lawyer [7]
3 years ago
14

What is the difference of the fractions? Use the number line to help find the answer. 1/2 - 1 1/5​

Mathematics
1 answer:
hammer [34]3 years ago
4 0
5/10 - 22/10 , 22/10 -5/10 = 17/10 is the difference I think
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Which Expression Can Be Used To Determine the nth term in the pattern below<br> 20,25,30,35,40
maw [93]

Answer:

see explanation

Step-by-step explanation:

These are the terms of an arithmetic sequence with n th term

a_{n} = a + (n - 1)d

where a is the first term and d the common difference

d = 25 - 20 = 30 - 25 = 5 and a = 20, hence

a_{n} = 20 + 5(n - 1) = 20 + 5n - 5 = 5n + 15 ← n th term formula

8 0
3 years ago
If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes
anyanavicka [17]

ANSWER

x  =  2 \: \: or \:  \:  x  =  15

Or

x  =   - 2 \: \: or \:  \:  x  =   -  15

EXPLANATION

The given polynomial is

f(x) = {x}^{2}  + kx + 30

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

m + n =  -  \frac{b}{a}  =  -k

and the product of roots is

mn =  \frac{c}{a}  = 30

The square difference of the zeroes is given by the expression.

( {m - n})^{2} =  {(m + n)}^{2} - 4mn

From the question, this difference is 169.

This implies that:

( { - k)}^{2}  - 4(30) = 169

{  k}^{2}  -120= 169

k^{2} = 289

k=  \pm \sqrt{289}

k=  \pm17

We substitute the values of k into the equation and solve for x.

f(x) = {x}^{2}   \pm17x + 30

f(x) = (x  \pm2)(x  \pm 15)

The zeroes are given by;

(x  \pm2)(x  \pm 15) = 0

x  =  \pm2 \: \: or \:  \:  x  =  \pm 15

5 0
3 years ago
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