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Dovator [93]
3 years ago
13

What is the constant of proportionality in the equation y = 5/3x?

Mathematics
1 answer:
djyliett [7]3 years ago
4 0

Answer:

x = 98

Step-by-step explanation:

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The sum of three numbers is 110. The third number is 3 times the first. The second number is 5 more than the first. What are the
g100num [7]

Answer:

The numbers are 63, 26, & 21

Step-by-step explanation:

110 = 3x + (5 + x) + x

105 = 3x + 2x

105 = 5x

21 = x

Plug it back into the first equation to find your values

6 0
3 years ago
X/3=-19<br> What is the value of x
Molodets [167]
<h3>I'll teach you how solve X/3=-19</h3>

-----------------------------------------------

X/3=-19

Multiply both sides by 3:

3x/3= 3(-19)

Simplify:

x= -57

Your Answer Is x= -57

plz mark me as brainliest :)

8 0
3 years ago
Read 2 more answers
X = 5y/(z-4y) <br><br> make y subject
Margarita [4]

Answer:

y=2x/5-4x

Step-by-step explanation:

multiply z-4y on both sides,match the Ys together and then make y common

3 0
2 years ago
Can someone translate this into a verbal expression 3(4j + 4 + j)?
dalvyx [7]
3(5j+4)
15j+12

final answer 15j+12
5 0
3 years ago
Could someone help me rnnn?
GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola:  y=3x^2-4

Step-by-step explanation:

Given:

  • y-intercept of parabola: -4
  • parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola:  y=a(x-h)^2+k

(where (h, k) is the vertex and a is some constant)

Substitute point (0, -4) into the equation:

\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}

Substitute point (-2, 8) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}

Substitute point (1, -1) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}

Equate to find h:

\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}

Substitute found value of h into one of the equations to find a:

\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}

Substitute found values of h and a to find k:

\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}

Therefore, the equation of the parabola in vertex form is:

\implies y=3(x-0)^2-4=3x^2-4

So the vertex of the parabola is (0, -4)

5 0
3 years ago
Read 2 more answers
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