Answer:
Step-by-step explanation:
Given
m∠COD=8x+13,
m∠BOC=3x-10, and
m∠BOD=12x-6
The following addition property is true;
<BOD = <BOC + <COD
Substitute
12x-6 = 3x-10+8x+13
12x-6 = 11x+3
12x-11x = 3+6
x = 9
Get <BOD
<BOD = 12x-6
<BOD = 12(9)-6
<BOD = 108-6
<BOD = 102°
That person;s body weight will be 156 Ib. Do 9 3/4 times 1/16 to get you body weight
Answer:
39.50
42.50
Step-by-step explanation:
Age of the 2 men = sum of the ages of the 6 men - sum of the ages of the 4 men
Average = sum of ages / total number of men
35 = sum of ages / 6
sum of ages = 35 x6 = 210
32 = sum of ages / 4
32 x 4 = sum of ages
128
210 - 128 = 82
age of the younger man = x
age of the older man = 3 + x
x + 3 + x = 82
2x + 3 = 82
2x = 82 - 3
2x = 79
x = 79/2 = 39.5
older man = 39.5 + 3 = 42.50
