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Bas_tet [7]
2 years ago
8

For Exercises 19-24, suppose m is the line with equation x = -5, line n is the line with equation y = 1, line g is the line with

equation y = x, and line h is the line with equation y = -2. Given A(9,-3), B(6,4), and c(-1,-5), what are the coordinates of the vertices of AA'B'C' for each reflection?
22. Rn

24. Rh​
Mathematics
1 answer:
shtirl [24]2 years ago
6 0

Answer:

dgff

Step-by-step explanation:

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3x-2y=10 3x-2y=14 solve using substitution or elimination. What's the answer?
CaHeK987 [17]
I hope this helps you



-3x+2y= -10


3x-2y=14



-3x+2y+3x-2y= -10+14


0+0= 6


0=6 false it's not inconsistent




8 0
3 years ago
Read 2 more answers
Similar Triangles
NeTakaya

Answer:

5.3 ft

Step-by-step explanation:

Because CD corresponds to BC, the scale factor from triangle ABC to triangle CDE, is 7/8. Now, DE corresponds to AB, so to get DE, we must multiply the value of AB by 7/8. 6 times 7/8 is 5.25, and rounding to the nearest tenth of a foot, the value of DE is 5.3.

3 0
3 years ago
A skull cleaning factory cleans animal skulls of​ deer, buffalo and other types of animals using​ flesh-eating beetles. the fact
Shtirlitz [24]
The solution for this problem is:
The population is 500 times bigger since 8000/24 = 500. The population after t days is computed by:P(t) = P₀·4^(t/49) 
Solve for t: 8000 = 8·4^(t/49) 1000 = 4^(t/49) log₄(1000) = t/49t = 49log₄(1000) ≅ 244 days
8 0
3 years ago
A 1L IV contains 60meq of kcal. The IV was discontinued after 400ml has infused. How much lvl did the patient receive
Leya [2.2K]

If a 1L IV contains 60meq of kcal and the IV was discontinued after 400ml has infused, then the amount of IV received by the patient is 24meq of kcal.

Calculation for the Amount of IV

It is given that,

1L IV contains 60meq of kcal

⇒ 1000 mL of IV contains 60meq of kcal

⇒ 1 mL of IV will contain 60 / 1000 meq of kcal

As per the question,

The amount of IV infused in the patient = 400 mL

⇒ The amount of IV received by the patient in meq of kcal = 400 × (60 / 1000)

= 4 × 6

= 24 meq of kcal

Hence, the patient receives 24meq of kcal amount of IV.

Learn more about amount here:

brainly.com/question/4567186

#SPJ1

6 0
2 years ago
Can't figure out this problem can anyone help if so thank you
Virty [35]

Answer:

10th term of the sequence = 0.537

Step-by-step explanation:

First three terms of the sequence are → 5, 4, \frac{16}{5}..........

Ratio of 2nd and 1st term of the sequence = \frac{4}{5}

Ratio of 3rd and 2nd term of the sequence = \frac{\frac{16}{5} }{4}

                                                                        = \frac{4}{5}

Therefore, ratio between every successive term to the previous term is common.

Common ratio 'r' = \frac{4}{5}

First term of the sequence 'a' = 5

nth term of a geometric sequence = a(r)^n

Therefore, nth term of the given term will be  T_n=5(\frac{4}{5})^n

Now we have to find the 10 term of the given sequence.

For n = 10,

T_{10}=5(\frac{4}{5})^{10}

      = 0.53687

      ≈ 0.537

Therefore, 10th term of the sequence is 0.537

7 0
3 years ago
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