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Black_prince [1.1K]
3 years ago
15

Solve each inequality 3+1/2(3-x)<-7

Mathematics
1 answer:
dimaraw [331]3 years ago
5 0

Answer:

You can download app to help you I hope you find your answer

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muminat
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Solve the following inequality for g. Write your answer in simplest form.<br> -5-3(5g-4)≥2g+6-10
denpristay [2]

Answer:

g\leq \frac{11}{17}

Step-by-step explanation:

-5-3(5g-4)\geq 2g+6-10\\-5+(-15g+12)\geq 2g-4\\-5+(-15g)+12\geq 2g-4\\7-15g\geq 2g-4\\7\geq 17g-4\\3\geq 17g\\\frac{11}{17} \geq g\\g\leq \frac{11}{17}

3 0
3 years ago
The circumference of a circle is 6 inches. What is the area of the circle?
Digiron [165]

Answer:

Step-by-step explanation:

6 0
3 years ago
−22 = −0.4k What does k equal to?
spin [16.1K]
Divide -22 by -0.4 and you’ll have your answer for k
6 0
3 years ago
Smplify the radical expression. How many different ways can you write your answer?
mel-nik [20]

Answer:

2xy\sqrt[3]{2x^2z} and 2xy(2x^2z)^{\frac{1}{3}}.

Step-by-step explanation:

The given radical expression is

\sqrt[3]{16x^5y^3z}

We have to simplify the above expression.

The above expression can be written as

\sqrt[3]{(2\times 8)(x^{3+2})y^3z}

\sqrt[3]{(2\times 2^3)(x^3\times x^2)y^3z}    [\because a^{m+n}=a^ma^n]

\sqrt[3]{(2^3x^3y^3)(2x^2z)}

\sqrt[3]{(2xy)^3}\sqrt[3]{2x^2z}    [\because (ab)^m=a^mb^m]

2xy\sqrt[3]{2x^2z}    [\because \sqrt[n]{x^n}=x]

It can be written as exponent form.

2xy(2x^2z)^{\frac{1}{3}}    [\because \sqrt[n]{a}=a^{\frac{1}{n}}]

Therefore, the required expressions are 2xy\sqrt[3]{2x^2z} and 2xy(2x^2z)^{\frac{1}{3}}.

5 0
3 years ago
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