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german
3 years ago
7

What is it please????

Mathematics
1 answer:
Marysya12 [62]3 years ago
8 0

Answer:

Step-by-step explanation:

In the equation of a straight line (when the equation is written as "y = mx + b"), ... This useful form of the line equation is sensibly named the "slope-intercept form". ... the slope of a given line measures how much the value of y changes for every ...

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What 5 numbers that round down to 600
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*It depends what place value needs to be rounded down, but without any specific place values, here are my answers*

<em>600.1</em>

<em>601</em>

<em>600.44</em>

<em>602.1</em>

<em>644.4</em>
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-Hope this helps :)


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4 years ago
What is the percent decline, to the nearest whole number, of rusty patched bumble bees from 20 years ago to today?
Andrej [43]
Sasuke is pretty cool
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3 years ago
Read 2 more answers
Which of the following is NOT a function help pls!
xxMikexx [17]

Step-by-step explanation:

In a function, the x factor will not repeat. I does not matter if the y repeats, but the x will not repeat in a true function. for example (2,4) (1,4) (5,9) is a function, but (2,4) (2,1) (5,9) is NOT a function

3 0
3 years ago
How do you solve this system of linear equation by substitution <br><br>x-3y=-12<br>y=2x+9
Ainat [17]
Finding x:
If y=2x+9, substitute y into the equation x-3y=-12.
You will get:  x-3(2x+9)=-12
Now, distribute:  x-6x-27=-12
Add like terms:  -5x-27=-12
Add 27 to both sides:  -5x=15
Divide both sides by -5:  x=-3

Now, substitute this value of x into the equation to find y:  y=2(-3)+9
Multiply:  y=-6+9
Add:  y=3

Here is the solution:  (x,y)=(-3,3)

Hope this explanation helped!




6 0
3 years ago
Which equation represents the formula for the general term, gn, of the geometric sequence 3, 1, 1/3, 1/9, . . .?
dedylja [7]

Answer:

Explicit form: g_n=3(\frac{1}{3})^{n-1}

Recursive form: g_n=\frac{1}{3}g_{n-1} with g_1=3.

Step-by-step explanation:

The first term is 3 and we are dividing by 3 each time.

Another way to say we are dividing by 3 each time is to say we are multiplying by factors of 1/3.

If the first term is a and r is the common ratio then the geometric sequence in explicit form is:

a_n=a(r)^{n-1}

g_n=3(\frac{1}{3})^{n-1}

The recursive form for a geometric sequence is a_n=ra_{n-1} with a_1=a where r is the common ratio and a is the first term.

So the recursive form for our sequence is g_n=\frac{1}{3}g_{n-1} with g_1=3.

6 0
3 years ago
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