Answer:
a. N=25
b. X[bar]= 60.52
c. Y[bar]= 106.72
d. SSx= 115.24
e. ∑X*∑Y = 4036684
f. SSxy= 202020.3296
g. √(SSx*SSy)= 449.46
Step-by-step explanation:
Hello!
Using the attached data you need to calculate some statistics.
a) N
The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.
b.
The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52
∑X is listed in the second table.
c.
The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72
∑Y is listed in the second table.
d.
Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24
e.
∑X*∑Y =1513*2668= 4036684
f.
SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296
g.
√(SSx*SSy)= √(115.24*1753)= 449.46
I hope you have a SUPER day!
<span>(X^2+6)(4x-3)
</span><span>=<span><span>(<span><span>x2</span>+6</span>)</span><span>(<span><span>4x</span>+<span>−3</span></span>)</span></span></span><span>=<span><span><span><span><span>(<span>x2</span>)</span><span>(<span>4x</span>)</span></span>+<span><span>(<span>x2</span>)</span><span>(<span>−3</span>)</span></span></span>+<span><span>(6)</span><span>(<span>4x</span>)</span></span></span>+<span><span>(6)</span><span>(<span>−3</span><span>)
</span></span></span></span></span>4x3−3x2+24x−18 is the answer
It is important to remember that weight is not the same as mass - the weight of an object and its mass are directly proportional . This means that for a given gravitational field strength, the greater the mass of the object, the greater its weight.
Answer:
- D. y + 10 = 1/8* (x + 32)
Step-by-step explanation:
Use the given points to work out the equation of the line.
<u>Find the slope:</u>
- m = (- 10 - (-4)) / (- 32 - 16) = - 6 / - 48 = 1/8
<u>Use (-32, - 10) and point- slope form:</u>
- y - (- 10) = 1/8*(x - (-32))
- y + 10 = 1/8* (x + 32)
Correct choice is D
Answer:
Step-by-step explanation:
Given data:
random sample size n = 1000
Population size is N - 2,000,000
P = 0.49
We know
Probability for having X =520
sample proportion 
