You first wanna find <BAD, because if AB is perpendicular to AC, then it has to form a 90 degree angle. So 90-56=34 degrees. So now you have a 34 & 63 degrees in the ABD triangle. In a triangle, all angles add up to equal 180 degrees. So 34+63+x=180...and x=83. So <ADB= 83 degrees. Now you want to find angle ADC...which you can just subtract 83 from 180 (because <ADB & <ADC forms 180 degree angle). You will then get 97 as angle ADC. So, the same thing as before, add up 56+97+x=180, because all angles (in the triangle ADC) add up to be 180 degrees. X will then equal 27 degrees. Angle ACB= 27 degrees.
Answer:
d.5/3
Step-by-step explanation:
m=y2-y1/x2-x1
m=8-3/9-6=5/3
Answer:
the correct answer is d
Step-by-step explanation:
Answer:
b=3, y=6
Step-by-step explanation:
Label the 2 equations:
2b +6y= 42 -----(1)
2b +4y= 30 -----(2)
(1) -(2):
(2b +6y) -(2b +4y)= 42 -30
2b +6y -2b -4y= 12
2y= 12
y= 12 ÷2 <em>(</em><em>÷</em><em>2</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
y= 6
Susbt. y=6 into (2):
2b +4(6)= 30
2b +24=30
2b= 30 -24 <em>(</em><em>-24</em><em> </em><em>on</em><em> </em><em>b</em><em>o</em><em>t</em><em>h</em><em> </em><em>sides</em><em>)</em>
2b= 6
b= 6 ÷2
b= 3
