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koban [17]
3 years ago
13

N the proportion 6 over ten ​​ = ​k21 over k ​​ , the value of k is ​​

Mathematics
2 answers:
Reil [10]3 years ago
8 0

Answer:

t3teyetherh

Step-by-step explanation:

ehwrhthtyteheth

N76 [4]3 years ago
4 0

6/10 =21/k cross multiply

6k = 210 divide both sides by 6

k =320 / 6

k=35

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Cameron has a bag that contains one silver (S) and one gold (G) marble. The marbles are the same size. Cameron chooses one marbl
Harman [31]

Answer:

(SS,SG,GS,GG) Probability 0.25

Step-by-step explanation:

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6 0
3 years ago
Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin9t,sin6t,9t⟩,r(0)=⟨4,6,3⟩
klemol [59]

\mathbf r'(t)=\langle\sin9t,\sin6t,9t\rangle


\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt


\mathbf r(t)=\left\langle\displaystyle\int\sin9t\,\mathrm dt,\int\sin6t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle


\displaystyle\int\sin9t\,\mathrm dt=\frac19\cos9t+C_1

\displaystyle\int\sin6t\,\mathrm dt=\frac16\cos6t+C_2

\displaystyle\int9t\,\mathrm dt=\frac92t^2+C_3


With the initial condition \mathbf r(0)=\langle4,6,3\rangle, we find


\dfrac19\cos0+C_1=4\implies C_1=\dfrac{35}9

\dfrac16\cos0+C_2=6\implies C_2=\dfrac{35}6

\dfrac92\cdot0^2+C_3=3\implies C_3=3


So the particular solution to the IVP is


\mathbf r(t)=\left\langle\dfrac19\cos9t+\dfrac{35}9,\dfrac16\cos6t+\dfrac{35}6,\dfrac92t^2+3\right\rangle

4 0
3 years ago
Write an equation of the line that passes through (2,3) and is perpendicular to the line shown. Please help!!
sattari [20]

Answer:

7.0

Step-by-step explanation:

In ΔVWX, the measure of ∠X=90°, the measure of ∠W=9°, and WX = 8.7 feet. Find the length of XV to the nearest tenth of a foot.

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TiliK225 [7]

Answer and Step-by-step explanation:

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Total speed travelled = (0.50 + 0.00 + 0.40)miles/min = 0.90mile/min

The 0.00 represents the period he was at rest admiring an antique car. At this moment, he was not moving so his speed is 0.

Total distance travelled = total speed x total time = 0.90miles/min x 12min = 10.8miles

5 0
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A radio telescope has a parabolic surface, as shown below. If the telescope is 5 m deep and 40 m wide, how far is the focus from
Montano1993 [528]

Answer:

i think the answer is  8m

Step-by-step explanation:

4 0
3 years ago
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