All categories

2 years ago

What is 2x+3y=53 3x-y=19

Mathematics

2 answers:

chubhunter [2.5K]2 years ago

7 0

Answer:

(10,11)

Step-by-step explanation:

kykrilka [37]2 years ago

7 0

(10,11) is the answer

You might be interested in

one room length 12.8 and breadth equals to 850 CM inside that room there is a bad length is 300 cm and breadth is 400 cm find th

9966 [12]

Answer:

$Area = 968000cm^2$

Step-by-step explanation:

To be able to answer this question properly. I'll assume the length of the room is in meters.

So for the room, we have:

$Length = 12.8m$

$Breadth = 850cm$

For the bed, we have:

$Length = 300cm$

$Breadth = 400cm$

First, we calculate the surface area of the room.

$A_1 = 12.8m * 850cm$

Convert all units to cm

$A_1= 12.8*100cm * 850cm$

$A_1= 1 088 000 cm^2$

Next, we calculate the area of the bed

$A_2 = 300cm * 400cm$

$A_2 = 120000cm^2$

The area of the space left is the difference between A1 and A2

$Area = A_1 - A_2$

$Area = 1088000cm^2 - 120000cm^2$

$Area = 968000cm^2$

5 0

2 years ago

What is the expanded form of 114006

aalyn [17]

In expanded form :
100,000+10,000+4,000+6

5 0

3 years ago

Read 2 more answers

Please help. Thank you.

Trava [24]

Answer:

By the Pythagoras theorem, the hypotenuse (c), is equivalent to:

a^2+ b^2= c^2 where a and b are the other two sides of the right angled triangle, hence c= square root (15^2+ 20^2)= 25

4 0

2 years ago

The point of the concurrence of all angle bisectors of a triangle is called the?

wolverine [178]

Answer:

Incenter is the answer.

Hope it helps!!!

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The value of a house decreases at a steady rate of 20% each year. What is the total percentage loss (to the nearest integer) in

Westkost [7]

Answer: The total percentage loss would be 67%.

Step-by-step explanation:

Since we have given that

Rate of decline each year = 20%

Number of years = 5

We need to find the total percentage loss in value of the house at the end of 5 years.

So, Total percentage loss would be

$1-(1-\dfrac{r}{100})^5\\\\=1-(1-\dfrac{20}{100})^5\\\\=1-(\dfrac{4}{5})^5\\\\=1-(0.8)^5\\\\=0.67\\\\\approx 67%$

Hence, the total percentage loss would be 67%.

8 0

2 years ago