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Fiesta28 [93]
3 years ago
5

What is the solution of the equation when solved over the complex numbers?

Mathematics
2 answers:
olga55 [171]3 years ago
5 0

Answer:

x = 5.2 or x = -5.2

Step-by-step explanation:

lyudmila [28]3 years ago
5 0

Answer:

The solution to the quadratic equations are:

x=3\sqrt{3}i,\:x=-3\sqrt{3}i

Step-by-step explanation:

Consider the provided quadratic equation.

x^2+27=0

Subtract 27 from both sides.

x^2+27-27=-27

x^2=-27

x=\pm \sqrt{-27}

x=\pm 3 \sqrt{3}i    ∴i=√-1

Hence, the solution to the equation are:

x=3\sqrt{3}i,\:x=-3\sqrt{3}i

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Answer:

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If we want to find any possible outliers we can use the following formulas for the limits:

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And if we find the lower limt we got:

Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3

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So then the left boundary for this case would be 3 days

Step-by-step explanation:

For this case we have the following 5 number summary from the data of 144 values:

Minimum: 9 days

Q1: 18 days

Median: 21 days

Q3: 28 days

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The IQR is given by:

IQR = Q_3 -Q_1 = 28-18= 10

If we want to find any possible outliers we can use the following formulas for the limits:

Lower= Q_1 - 1.5 IQR

Upper= Q_3 + 1.5 IQR

And if we find the lower limt we got:

Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3

Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43

So then the left boundary for this case would be 3 days

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Step-by-step explanation:

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