Hello,
Pease, see the attached file.
Thanks.
Answer:
a) there is s such that <u>r>s</u> and s is <u>positive</u>
b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r
Step-by-step explanation:
a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.
b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.
5/16 multiply the denominator by 2 and add 1 to the numerator
9/32 multiply the denominator by 4 and add 1 to the numerator
10/32 multiply the denominator by 4 and add 2 to the numerator
Answer:
1.97-20= -18.03
20-1.97= 18.03
Step-by-step explanation:subtract the numbers from each other.
