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Vinvika [58]
3 years ago
14

Jack and Jill start driving from the same location. Jack drives 30 miles south while Jill drives west. If Jack and Jill are 78 m

iles apart when they stop, how many miles west did Jill drive? Show all work in solving the problem.
Mathematics
1 answer:
arsen [322]3 years ago
5 0

Answer:

72 mles

Step-by-step explanation:

For better understanding, I'll make use of an attachment.

From the attachment,

O represents the start point

OB = 30 --- Jack

AB = 78 -- Distance between them

Required

Find OA; Jack's distance

To do this, we make use of Pythagoras theorem

AB^2 = OA^2 + OB^2

This gives:

78^2 = OA^2 + 30^2

6084 = OA^2 + 900

Subtract 900 from both sides

OA^2=  6084 - 900

OA^2=  5184

Take square roots

OA = \sqrt{5184}

OA = 72

<em>Hence, Jill drove 72 miles</em>

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Derivatives concept:
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9514 1404 393

Answer:

  A. y = -2x +13

  B. y = 8x -7

Step-by-step explanation:

A. We can read the y-intercept of the secant line from the graph. It is 13.

The slope can also be read from the graph, but we choose to use the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (19 -9)/(-3 -2) = 10/-5 = -2

Then the slope-intercept formula for the line is ...

  y = mx + b . . . . . . line of slope m and y-intercept b

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__

B. The vertex of the given parabola is (0, 1). We notice that when x=1 (1 unit right of the vertex), y = 3 (2 units up from the vertex). This tells us the vertical scale factor of the parabola is 2. That means the vertex form equation is ...

  y = a(x -h)^2 +k . . . . . . . . vertex (h, k), scale factor 'a'

  y = 2(x-0)^2 +1 . . . . . . . use known values for (h, k)

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The derivative of this is ...

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So, at x=2, the given point A, the slope of the tangent line is ...

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We have a point and the slope, so we can write the point-slope form of the equation for the tangent line:

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Rearranging to slope-intercept form, this is ...

  y = 8x -7

__

<em>Additional comment</em>

You can also read the slope of the tangent line from the graph. The line also goes through the point (1, 1), so has a rise of 8 for a run of 1. The y-intercept can be found from ...

  b = y -mx = 9 -8(2) = -7

This lets you write the equation of the tangent line directly from the graph.

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