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mariarad [96]
2 years ago
15

A trapezoid has an area of 60 square inches. The height of the trapezoid is 5 inches. What is the length of the longer base if t

he longer base is three times the length of the shorter base?
Mathematics
2 answers:
Gwar [14]2 years ago
6 0

Answer:

C

Step-by-step explanation:

Vinil7 [7]2 years ago
5 0

Answer:

Step-by-step explanation:

Remark

Let the shorter base = x

Let the longer base = 3x

h = 5

Area = 60

Formula

Area = (b1 + b2)*h /2

Solution

60 = (x + 3x)*5 / 2                Multiply both sides by 2

2*60 = (x + 3x)*5                  Combine like terms

120 = 4x *5

120 = 20x                             Divide by 20

120/20 = x

x = 6

Therefore the two bases are

x = 6

3x = 18

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The length of the garden is 10 feet more than twice its width. The perimeter of the garden is 170 feet.
icang [17]

Answer:

The width of the garden is 25 feet

The length of the garden is 60 feet

Step-by-step explanation:

The formula for the perimeter of a rectangle

= P = 2L + 2W

Where L = Length, W = Width

The length of the garden is 10 feet more than twice its width.

P = 170

L = 2W + 10

Hence,

170 = 2(2W + 10) + 2W

170 = 4W + 20 + 2W

Collect like terms

170 - 20 = 6W

150 = 6W

W = 150/6

W = 25 feet

The width of the garden is 25 feet

Remember

L = 2W + 10

L = 2(25) + 10

L = 50 + 10

L = 60 feet

The length of the garden is 60 feet

3 0
2 years ago
Simplify the fraction.
Leona [35]
I hope this helps you



42/98



2.3.7/2.7.7



3/7
3 0
2 years ago
Read 2 more answers
For the period 1997-2003, the number of eggs y (in billions) produced in the United States can be modeled by the function y=-0.2
Viktor [21]

Answer:

Part a) The approximate years were 1998 and 2008

Part b) The graph in the attached figure

Step-by-step explanation:

Part a) we have

y=-0.27x^{2}+3.3x+77

For y=80\ billion\ eggs

Solve the quadratic equation

80=-0.27x^{2}+3.3x+77

0.27x^{2}-3.3x+3=0

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

0.27x^{2}-3.3x+3=0

so

a=0.27\\b=-3.3\\c=3

substitute in the formula

x=\frac{3.3(+/-)\sqrt{-3.3^{2}-4(0.27)(3)}} {2(0.27)}

x=\frac{3.3(+/-)\sqrt{7.65}} {0.54}

x=\frac{3.3(+)\sqrt{7.65}} {0.54}=11.23\ years

x=\frac{3.3(-)\sqrt{7.65}} {0.54}=0.99\ years

therefore

The approximate years are

1997+11=2008

1997+1=1998

Part b)

Using a graphing tool

we have

y=-0.27x^{2}+3.3x+77

y=80

The solution of the system of equations is the intersection point both graphs

The intersection point are (0.99,80) and (11.23,80)

see the attached figure

therefore

The solution part a) is correct

3 0
3 years ago
A mountaineer climbed 1,000 feet
stiks02 [169]

Answer:

please complete your question

8 0
2 years ago
Read 2 more answers
If x = 3 and Y = 5 work out the value of 2x squared + 3 Y squared
miskamm [114]

Answer:

Step-by-step explanation:

x = 3

y = 5

2x^2 + 3y^2 = 2 × 3^2 + 3 × 5^2

= 2 × 9 + 3 × 25

= 18 + 75

= 93

Hope this helps

plz mark as brainliest!!!!

4 0
3 years ago
Read 2 more answers
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