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serious [3.7K]
3 years ago
15

Boris invested his savings in two investment funds. The $12,000 that he invested in fund a returned a 6% profit the amount that

he invested in fund b returned at 2% profit how much did he invest in Fund b if both funds together returned a 5%
Mathematics
1 answer:
Sedbober [7]3 years ago
4 0

Answer:

$4000

Step-by-step explanation:

Let B represent amount invested in account 'b'.  

We have been given that an amount of $12,000 that Boris invested in fund a returned a 6% profit.

So the profit earned from fund 'a' would be 12,000\times\frac{6}{100}=12,000(0.06).

We are also told that the amount that he invested in fund b returned at 2% profit. So the profit earned from fund 'b' would be B\times\frac{2}{100}=B(0.02)=0.02B.

Further, both funds together returned a 5%. We can represent this information as:

(12,000+B)\times\frac{5}{100}=0.05(12,000+B)

Now, we will equate profit earned from account 'a' and 'b' with profit earned from both accounts as:

12,000(0.06)+0.02B=0.05(12,000+B)

720+0.02B=600+0.05B

600+0.05B=720+0.02B

600-600+0.05B=720-600+0.02B

0.05B=120+0.02B

0.05B-0.02B=120+0.02B-0.02B

0.03B=120

\frac{0.03B}{0.03}=\frac{120}{0.03}

B=4000

Therefore, Jason invested $4000 in fund 'b'.

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PLEASE HELP ASAP !!
wariber [46]

Answer:

     <u>First figure:</u>            954cm^3

     <u>Second figure:</u>      1,508yd^3

     <u>Third figure:</u>

  •          Height= q
  •           Side length = r

     <u>Fourth figure: </u>        726cm^3

Explanation:

<u></u>

<u>A. First figure:</u>

<u>1. Formula:</u>

            \text{Volume of a cylinder}=\pi \times radius^2\times length

<u>2. Data:</u>

  • radius = 9cm / 2 = 4.5cm
  • length = 15 cm

<u>3. Substitute in the formula and compute:</u>

          Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3

<u>B. Second figure</u>

<u>1. Formula: </u>

       \text{Volume of a leaned cylinder}=\pi \times radius^2\times height

<u>2. Data:</u>

  • radius = 12yd
  • height = 40 yd

<u>3. Substitute and compute:</u>

      Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3

<u></u>

<u>C) Third figure</u>

a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u>  </u><u>q  </u>.

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e.<u>  r </u><u> </u>.

When the base of the pyramid is a square the four edges of the base have the same side length.

<u>D) Fourth figure</u>

<u>1. Formula</u>

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

          Volume=(1/3)B\times H

<u>2. Data: </u>

  • height: H = 18cm
  • side length of the base: 11 cm

<u>3. Calculations</u>

a) <u>Calculate the area of the base</u>.

The base is a square of side length equal to 11 cm:

          \text{Area of the base}=B=(11cm)^2=121cm^2

b) <u>Volume of the pyramid</u>:

         Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3

4 0
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Explanation:

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givi [52]
As given he made  3/5 of basket he shot.

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So if total number of shot is 60.

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