The pattern is plus 10 for each time
Formula recursive
A_n = A_n -1 + 10
So the next term is 5th
A_5 = A_5 -1 + 10
A_5-1 = A_4 +10
5th = 6+10 = 16
I think you can do it for the next 2 terms.
Answer:
use the formula pi r 2 and simply multiply 3.14 times 16.
Answer:
Step-by-step explanation:
A
(2x - 5)(x + 1)
B)
The x intrcepts occur when the factors equal zero.
2x - 5 = 0
2x = 5
x = 5/2
x = 2 1/2
C
I will give the the minimum from completing the square
y = 2(x - 0.75)^2 - 6.125
as x approaches + infinity, y approaches + infinity.
as x approaches - infinity, y approaches + infinity.
It's a quadratic. The y values go to plus infinity, when x goes from - infinity to + infinity.
D
Desmos is the most useful tool for this part of the question. What it shows is the two roots and the minimum at (0.75,-6.125. A parabola does what the end behavior describes. The roots are clearly labeled as is the minimum.
Answer:
i really don't know it soooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo
Step-by-step explanation:
Answer:
there would be 40 gold notebooks
Step-by-step explanation:
if the ratio is 5g to 3r i took the 24 red and divided it by 3 which gave me 8. I then multiplied 8 by 5 and got 40. so 40:24 is equal to 5:3