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The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
<h3>How to represent the
quadratic function in standard form?</h3>
The quadratic function is given as
f(x) = -3x^2 + 6x - 2
The standard form of a quadratic function is represented as:
f(x) = ax^2 + bx + c
When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form
Where
a = -3
b = 6
c = -2
Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
Read more about quadratic function at
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Tangent always meets radius at 90° angle.
Angle ABC = 90° so Pythagoras' theorem applies.
r² + 4² = (r+2)²
r² + 16 = r² + 4r + 4
12 = 4r
r = 3
Answer:
(5x + 2) - (-9x - 2)
O 11x2 – 5x + 8
14x + 4
–6x2 + 8x 7
-X2 + 6
Step-by-step explanation:
MrBillDoesMath!
Answer: 51,53,55,57
Discussion. By the triangle inequality the sum of the lengths of any two sides is greater than or equal to the third side. In our case, 3 + 54 = 57, so the third side must be less than or equal to 57.
MrB
