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2 years ago

Nancy gets a Math assignment every 10 days. She gets a Science assignment every 12 days.

Mathematics

2 answers:

ra1l [238]2 years ago

8 0

On the fifth day. you are basically finding the least common multiple of these numbers

ExtremeBDS [4]2 years ago

8 0

She gets 22 so that is. The answer because you are adding

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Help, please! This question may take some time to answer.

tatyana61 [14]

Answer:

0.15-0.75p? YES

-0.45-0.6+0.75P? NO

-3(-0.05+0.25p)? YES

-3(0.15)+(-3)(0.2)+(-3)(0.25p)? NO

Step-by-step explanation:

-3(0.15-0.2+0.25p)

=-0.45+0.6-0.75p

=0.15-0.75p

1. 0.15-0.75p=0.15-0.75p? YES

2. -0.45-0.6+0.75P=0.15-0.75p?

-1.05+0.75p=0.15-0.75p? NO

3. -3(-0.05+0.25p)=0.15-0.75p?

0.15-0.75=0.15-0.75p? YES

4. -3(0.15)+(-3)(0.2)+(-3)(0.25p)=0.15-0.75p?

-0.45-0.6-0.75p=0.15-0.75p?

-1.05-0.75p=0.15-0.75p? NO

7 0

2 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

3 years ago

Find the cosine of each acute angle

Lemur [1.5K]

Answer:

cos P = 53 degrees

cos Q = 37 degrees

Step-by-step explanation:

cos P = $\frac{adjacent}{hypothenuse}$

cos P = $\frac{24}{40}$

cos P = 0.60

Cos-1 of 0.60 is 53.13 (round to the nearest whole number)

cos P = 53 degrees

cos Q = $\frac{adjacent}{hypothenuse}$

cos Q = $\frac{32}{40}$

cos Q = 0.80

Cos of 0.80 is 36.86 (round to the nearest whole number)

cos Q = 37 degrees

To check anser:

90 + 53 + 37 = 180

180 = 180

4 0

2 years ago

Hey y’all , please give me the correct answer.

eduard

Answer:

-s-6>-7

Step-by-step explanation:

Just ask!

Hope this helps. :)

6 0

1 year ago

Read 2 more answers

Jane, Scott, and Frank have a total of $144 in their wallets. Frank has 4 times what Jane has. Scott has $6 less than Jane. How

konstantin123 [22]

Answer:

Jane have $25

Frank have $100

Scott have $19

Step-by-step explanation:

To find the amount that each have, we have to represent this information in a mathematical format and then solve

let x represent represent the amount that Jane has

let Y represent represent the amount that Frank has

let z represent represent the amount that Scott has

From the question given, "Jane, Scott, and Frank have a total of $144" can be represented mathematically as

x + y + z = $144 ---------------------------------------------------------------------------------(1)

"Frank has 4 times what Jane has" can be represented mathematically as

y = 4x ---------------------------------------------------------------------------------------------(2)

"Scott has $6 less than Jane" can be represented mathematically as

z= x- 6 ----------------------------------------------------------------------------------------------(3)

we can now solve the equations using the substitution method

substitute equation (2) and (3) into equation (1)

x + y + z = $144

x + 4x + x-6 = $144

6x -6 = $144

add 6 to both-side of the equation

6x - 6 + 6 = $144 + 6

6x =$150

Divide both-side of the equation by 6

6x/6 = 150/6

x = $25

from equation 2

y = 4x

substitute x= $25 in equation (2)

y = 4 (25)

y = $100

substitute x=$25 in equation (3)

z = x- 6

z = 25 - 6

z=$19

Jane have $25

Frank have $100

Scott have $19

6 0

2 years ago