Answer:
Case(a): ![p[b]=\frac{1}{3}p[a]](https://tex.z-dn.net/?f=p%5Bb%5D%3D%5Cfrac%7B1%7D%7B3%7Dp%5Ba%5D)
Case(b): ![p[b]=0](https://tex.z-dn.net/?f=p%5Bb%5D%3D0)
Case(c): ![p[b]=\frac{1}{2}p[a\cap b]](https://tex.z-dn.net/?f=p%5Bb%5D%3D%5Cfrac%7B1%7D%7B2%7Dp%5Ba%5Ccap%20b%5D)
Step-by-step explanation:
Given
(a) events a and b are a partition and p[a] = 3p[b].
(b) for events a and b, p[a ∪ b] = p[a] and p[a ∩ b] = 0.
(c) for events a and b, p[a ∪ b] = p[a]− p[b].
we have to find the p[b] in each case:
Case (a): events a and b are a partition and p[a] = 3p[b].
gives
Case (b): for events a and b, p[a ∪ b] = p[a] and p[a ∩ b] = 0.
![p[a\cup b]=p[a]](https://tex.z-dn.net/?f=p%5Ba%5Ccup%20b%5D%3Dp%5Ba%5D)
⇒![p[a]+p[b]-p[a\cap b]=p(a)](https://tex.z-dn.net/?f=p%5Ba%5D%2Bp%5Bb%5D-p%5Ba%5Ccap%20b%5D%3Dp%28a%29)
⇒ ∵ p[a ∩ b] = 0.
Case(3): for events a and b, p[a ∪ b] = p[a]− p[b].
p[a ∪ b] = p[a]− p[b]
⇒ ![p[a]+p[b]-p[a\cap b]=p[a]-p[b]](https://tex.z-dn.net/?f=p%5Ba%5D%2Bp%5Bb%5D-p%5Ba%5Ccap%20b%5D%3Dp%5Ba%5D-p%5Bb%5D)
⇒ ![2p[b]=p[a\cap b]](https://tex.z-dn.net/?f=2p%5Bb%5D%3Dp%5Ba%5Ccap%20b%5D)
⇒
You have to multiply 3 by 10 and 8 by 3, then subtract them
30/80 - 24/80 = 6/80
then simplify
6/2 and 80/2
3/40
Answer: $1904.60
Step-by-step explanation:
This is 1500(1+.04/4)^24 where .04/4 is the interest rate for each compounding, or the interest rate /4, for 4 quarters.
The 24 is 4 quarters/year * 6 years
round at the end
=$1904.60
<em>hope this helped!:)</em>
Answer:
( x + 3)² + ( y + 7)² = 361
Step-by-step explanation:
The equation of a circle written in standard form is ( x – h)² + ( y - k)² = r². The center is (h, k) and the radius is r.
With the given information of center (-3, -7) and radius 19, we get
[ x – (-3)]² + [ y - (-3)]² = (19)²
( x + 3)² + ( y + 7)² = 361
Answer:
-1 - 3
—————-
5-0
Step-by-step explanation:
