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Zolol [24]
3 years ago
10

Question is shown below ↓

Mathematics
1 answer:
sladkih [1.3K]3 years ago
7 0

\bf \stackrel{\textit{using the exponential model}}{N=2^D}~\hspace{7em}\begin{array}{ccll} \stackrel{days}{D}&\stackrel{\$}{N}\\ \cline{1-2} 1&2^1\implies 2\\ 2&2^2\implies 4 \end{array}

so, using that exponential model, the 1st output value works, but the second value of 2² does not give us 8 as output.

let's check the linear model using slopes to get the equation.

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{8})\qquad \impliedby \begin{array}{|cc|ll} \cline{1-2} D&N\\ \cline{1-2} 1&2\\ 2&8\\ \cline{1-2} \end{array}

\bf slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{8-2}{2-1}\implies \cfrac{6}{1}\implies 6 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=6(x-1) \\\\\\ y-2=6x-6\implies y=6x-4

now, using that model, x = 6, then y = 6(6) - 4, or y = 32.

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Step-by-step explanation:

The association can be found as the quotient between the elements with a given characteristic and the total number of elements.

For example, in option A we have:

A. Females prefer drama movies.

There are 72 females who like drama movies, and there is a total of 126 females, the quotient is:

Q = 72/126 = 0.57

This is the relative frequency of females who like's drama movies

Then the relative frequency table will be something like:

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who prefer drama: Q = 15/125 = 0.12

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who prefer comedy: Q = 36/126 = 0.29

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who prefer thriller: Q = 18/125 = 0.14

Now we want to answer, which one of the given options has the strongest association.

As larger is the value Q, larger is the association.

We can clearly see that, from the given options, the strongest association is for females who prefer drama, then the correct option is A.

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Hope this helped!

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