Check the picture below.
notice the alternate interior angles in the picture.
![\bf tan(68^o)=\cfrac{\stackrel{opposite}{1.5}}{\stackrel{adjacent}{x}}\implies x=\cfrac{1.5}{tan(68^o)}\implies x\approx 0.61 \\\\[-0.35em] ~\dotfill\\\\ tan(56^o)=\cfrac{\stackrel{opposite}{1.5}}{\stackrel{adjacent}{w}}\implies w=\cfrac{1.5}{tan(56^o)}\implies w\approx 1.01 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{width of the crater}}{x+w\implies 1.62}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20tan%2868%5Eo%29%3D%5Ccfrac%7B%5Cstackrel%7Bopposite%7D%7B1.5%7D%7D%7B%5Cstackrel%7Badjacent%7D%7Bx%7D%7D%5Cimplies%20x%3D%5Ccfrac%7B1.5%7D%7Btan%2868%5Eo%29%7D%5Cimplies%20x%5Capprox%200.61%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20tan%2856%5Eo%29%3D%5Ccfrac%7B%5Cstackrel%7Bopposite%7D%7B1.5%7D%7D%7B%5Cstackrel%7Badjacent%7D%7Bw%7D%7D%5Cimplies%20w%3D%5Ccfrac%7B1.5%7D%7Btan%2856%5Eo%29%7D%5Cimplies%20w%5Capprox%201.01%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bwidth%20of%20the%20crater%7D%7D%7Bx%2Bw%5Cimplies%201.62%7D~%5Chfill)
Answer:
5 bars
Step-by-step explanation:
Distance from a point to a line (Coordinate Geometry)
Method 1: When the line is vertical or horizontal
, the distance from a point to a vertical or horizontal line can be found by the simple difference of coordinates
. Finding the distance from a point to a line is easy if the line is vertical or horizontal. We simply find the difference between the appropriate coordinates of the point and the line. In fact, for vertical lines, this is the only way to do it, since the other methods require the slope of the line, which is undefined for evrtical lines.
Method 2: (If you're looking for an equation) Distance = | Px - Lx |
Hope this helps!
Answer:
Answer: -15x3y7
Step-by-step explanation:
The answer is 1/2. Is it right?
