Square <span>polygon is always regular, other have some scenarios which makes them regular but they are not always regular.</span>
The width of the rectangle is twice the length of the rectangle
<h3>How to compare the dimensions of the rectangle?</h3>
The given parameters are:
Width = 4 cm
Length = 2 cm
Express 4 cm as 2 * 2 cm
Width = 2 * 2 cm
Substitute Length = 2 cm in Width = 2 * 2 cm
Width = 2 * Length
This means that the width of the rectangle is twice the length of the rectangle
Hence, the true statement is that the width of the rectangle is twice the length of the rectangle
Read more about rectangles at:
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Answer:
URGENT
Debug the following:any one free out
sin theta equals to cos theta then the value of sin 2 theta
The error is in the second step they subtracted 3 from both sides but it was a 3x, which you can not do.
Correction.
9x+18+3x=1
12x+18=1
12x=-17
x=-17/12
What do you mean by solve?
Put in slope-intercept form would be: y<(3/4)x+1
