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frez [133]
3 years ago
14

ILL MARK BRAINIEST IF YOU CAN DO THESE 2 QUESTIONS RIGHT!!!

Mathematics
2 answers:
spayn [35]3 years ago
5 0

Answer:

C

Step-by-step explanation:

dont know the 2nd :(

Stella [2.4K]3 years ago
3 0

Answer:

1) p = 0.75n

2) 17 children

Step-by-step explanation:

1.50 ÷ 2 = 0.75 which is the price per mango

177.50 = 50 + 7.5n

127.5 = 7.5n

n = 17

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Find the interquartile range (IQR) of the data in the dot plot below.
Gala2k [10]

Answer: According to the picture the IQR would be 3.5

Step-by-step explanation:

4 0
3 years ago
Find the least common multiple of 4 and 10
Irina18 [472]

Answer:

20

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLZ HELP ME ASAP PLZ PLZ PLZ!!!!! I NEED LOTS OF HELP!!! I USED 40 POINTS
cupoosta [38]
First, some defintions
reciprocals are like a/b and b/a or 5/1 and 1/5

remember, \frac{\frac{a}{b}}{\frac{c}{d}}=(\frac{a}{b})(\frac{d}{c})=\frac{ad}{bc}

john's fraction is reciprocal of sarah's
john=a/b
sarah=b/a

david multiplies his by sarah and gets 12/35
(b/a)(david)=12/35

multplies his number by john and gets 12/35
(a/b)(david)=15/7

hmmm

(b/a)(david)=12/35 and
(a/b)(david)=15/7

if we divide them then we do
\frac{(\frac{b}{a})(david)}{(\frac{a}{b})(david)}=\frac{\frac{12}{35}}{\frac{15}{7}}=
\frac{\frac{b}{a}}{\frac{a}{b}}=\frac{\frac{12}{35}}{\frac{15}{7}}=
(\frac{b}{a})(\frac{b}{a})=(\frac{12}{35})(\frac{7}{15})=
\frac{b^2}{a^2}=\frac{84}{525}=
\frac{b^2}{a^2}=\frac{4}{25}
square root both sides
\frac{b}{a}=\frac{2}{5}

therefor
b=2 and a=5

john's number is a/b=5/2
sarah's number is 2/5

david, hmm

sarah times david=12/35
2/5 times david=12/35
times both sides by 5/2
david=60/70
david=6/7

check other

john times david=15/7
5/2 times 6/7=15/7
30/14=15/7
15/7=15/7
true





sarah's favorite number is 2/5
john's favorite number is 5/2
david's favorite number is 6/7
6 0
3 years ago
Cameron said that the Y intercept of a quadratic function always tells the maximum value of the function. explain Cameron's erro
Leno4ka [110]

Answer:

We can have two cases.

A quadratic function where the leading coefficient is larger than zero, in this case the arms of the graph will open up, and it will continue forever, so the maximum in this case is infinite.

A quadratic function where the leading coefficient is negative. In this case the arms of the graph will open down, then the maximum of the quadratic function coincides with the vertex of the function.

Where for a generic function:

y(x) = a*x^2 + b*x + c

The vertex is at:

x = -a/2b

and the maximum value is:

y(-a/2b)

4 0
3 years ago
Find the lateral area of the regular pyramid<br><br> L.A. =
Arisa [49]

Answer:

FOR REGULAR PYRAMID with those dimension.

L.A = 96

FOR HEXAGONAL PYRAMID with those dimension

L.A = 171.71

Step-by-step explanation:

Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.

Hence I solved for both:

FOR REGULAR PYRAMID

Lateral Area (L.A) = 1/2* p * l

Where p = Perimeter of base

P = 4s

P = 4 * 6

P = 24cm

l = slanted height

l = 8cm

L.A = 1/2 * 24 * 8

L.A = 1/2 ( 192)

L.A = 96cm ^ 2

FOR AN HEXAGONAL PYRAMID

Lateral Area = 3a √ h^2 + (3a^2) / 4

Where:

a = Base Edge = 6

h = Height = 8

L.A = 3*6 √ 8^2 + ( 3*6^2) / 4

L.A = 18 √ 64 + ( 3 * 36) / 4

L.A = 18 √ 64 + 108/4

L.A = 18 √ 64+27

L.A = 18 √ 91

L.A = 18 * 9.539

L.A = 171.71

8 0
3 years ago
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