Answer:
O A. PQ = SU
Step-by-step explanation:
When two triangles are congruent then by CPCTC,
their corresponding parts ( angles and sides ) must be congruent.
In triangles PQR and STU,
Side PQ, QR and RP are corresponding to the sides ST, TU and US respectively,
Also, angles P, Q and R are corresponding to angles S, T and U respectively.
Here, Δ PQR ≅ Δ STU,
Thus, by the above property,
PQ ≅ ST, QR ≅ TU and RP ≅ US,
∠P ≅ ∠T, ∠Q ≅ ∠T and ∠R ≅ ∠U
The trapezoid has two right triangles each with one side of length (13-9)2 = 4/2 = 2.
The other side of each right triangle is such that tan 60° = Heigth / 2
Then height = 2*tan60°.
The area of the trapezoid is height * (base 1 + base 2)/2
Then area = 2*tan (60°) * (13+9)/2 = 38.11
Let x be the unknown number. This means that "six times a number" becomes 6x. Finally, we want to compute the quotient between this quantity and 16, which leads to
The radius and the center of the circle are 4 units and (1,2), respectively
<h3>How to determine the center and the radius?</h3>
The center of the circle is on
y = 2x and x = 1
Substitute x = 1 in y = 2x
y = 2 * 1
Evaluate
y = 2
This means that the center is
Center = (1, 2)
Also, we have the point of tangency to be:
(x, y) = (1, 6)
This point and the center have the same x-coordinate.
So, the distance between this point and the center is
d = 6 - 2
d = 4
This represents the radius
Hence, the radius and the center of the circle are 4 units and (1,2), respectively
Read more about circle equation at:
brainly.com/question/10618691
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