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2 years ago

Solve the following quadratic-linear system of equations. y=x^2-x-6 and y=2x-2

2 answers:

8 0

You can do substitution 2x-2=x^2 -x -6; isolate all terms on one side 0= x^2 -x-2x -6+2; combine like terms x^2 -3x -4=0; factor the quadratic (x-4)(x+1)=0; each term is zero x-4=0 so x=4 and x+1=0 so x=-1. Now, y=2•4-2=6 and y=2•(-1) -2= -4 ; solutions for the system are ( 4,6) and ( -1, -4)

dimaraw [331]2 years ago

7 0

Answer:

(4,6) or (-1,-4)

Step-by-step explanation:

since both equations about x are equal to y, you can make x^2-x-6=2x-2

solve this quadratic equation, you get x=4 or -1

substitute x into y=2x-2

you get y=6 when x=4, or y= -4 when x=-1

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ololo11 [35]

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Now use the slope-intercept formula to find the y-intercept, b.

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Thus, the slope-intercept formula y = mx + b becomes 16 = -2(-3) + b.
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So now we have the slope and the y-intercept. Write the equation:

y = mx + b becomes y=-2x+10. Which of the four given answer choices is the correct one?

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2 years ago

Triangles O N M and S R Q are shown. Angles O N M and S R Q are congruent. The length of side N M is 10 and the length of side S

valina [46]

Answer:

Option C.

Step-by-step explanation:

In △ONM and △SRQ,

$\angle ONM\cong \angle SRQ$

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$QR=x$

We need to find the value of x that will make △ONM similar to △SRQ by the SAS similarity theorem.

According to SAS similarity theorem, two triangle are similar if two corresponding sides in both triangles are proportional and the included angle in both are congruent.

It is given that $\angle ONM\cong \angle SRQ$ . So, both triangles are similar by SAS if

$\dfrac{NO}{NM}=\dfrac{SR}{QR}$

Substitute the given values.

$\dfrac{8}{10}=\dfrac{20}{x}$

$8\times x=20\times 10$

$8x=200$

Divide both sides by 8.

$x=\dfrac{200}{8}$

$x=25$

Therefore, the correct option is C.

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3 years ago

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Aleksandr-060686 [28]

Hello from MrBillDoesMath!

Answer:

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3 years ago

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natima [27]

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2 years ago

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