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anzhelika [568]

3 years ago

14

Rachel has completed 16 assignments in the science course. This is 80% of all the assignments. How many total assignments will b

e in the science course?

1 answer:

Tresset [83]3 years ago

4 0

Answer:

20

Step-by-step explanation:

16 ÷ 80% = 20

80% of 20 is 16

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Slope of a parallel line with the points (7,-5) and (-5,7)

VLD [36.1K]

Answer: Negative 1 The slope of parallel lines is the same.

The attachment shows two such lines, given coordinates labeled.

Step-by-step explanation:

Find the slope of the line passing through the given points.

rise/run

Rise is the difference in y-values 7-(-5) = 12

Run is the difference between x-values -5 - 7 = - 12

The Slope is 12/-12 simplify:

slope = -1

5 0

3 years ago

Marc is looking at the plans for his new garage. the length of the garage is 8 metres. the scale on the drawing is 1:50. what wi

evablogger [386]

The answer is 16 cm (or 0.16 m).

The scale is the ratio of the model to the real thing.
So, in the scale 1:50, the model is 1, while the real thing is 50.
Now, just make a proportion:
the model : the real thing = the model dimension : the real thing dimension
1 : 50 = x : 8m

From here:
x = 8m * 1 / 50 = 0.16 m = 0.16 * 100 cm = 16 cm.

4 0

3 years ago

When determining if you have a perfect square trinomial, what must the first and third term be?

cricket20 [7]

The expansion of a perfect square is

$(a+b)^2 = a^2+2ab+b^2$

In words, the square of a sum of two terms is the sum of the squares of the two terms ( $a^2$ and $b^2$ ), plus twice the product of the two terms ( $2ab$ )

So, when determining if you have a perfect square trinomial, you should have two perfect squares. Note that they don't have to be the first and third term, since you can rearrange terms as you prefer.

8 0

3 years ago

What is the domain of the function y = RootIndex 3 StartRoot x minus 1 EndRoot?

finlep [7]

By definition of cubic roots and power properties, we conclude that the domain of the cubic root function is the set of all real numbers.

<h3>What is the domain of the function?</h3>

The domain of the function is the set of all values of x such that the function exists.

In this problem we find a cubic root function, whose domain comprise the set of all real numbers based on the properties of power with negative bases, which shows that a power up to an odd exponent always brings out a negative result.

<h3>Remark</h3>

The statement is poorly formatted. Correct form is shown below:

<em>¿What is the domain of the function </em> $y = \sqrt[3]{x - 1}$ <em>?</em>

<em />

To learn more on domain and range of functions: brainly.com/question/28135761

#SPJ1

4 0

1 year ago

(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

5 0

3 years ago