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larisa [96]
2 years ago
7

Nov. 1 Loaned $52,200 cash to C. Bohr on a 12-month, 7% note. Dec. 11 Sold goods to K. R. Pine, Inc., receiving a $1,800, 90-day

, 8% note. Dec. 16 Received a $4,800, 180-day, 10% note to settle an open account from A. Murdock. Dec. 31 Accrued interest revenue on all notes receivable.
Mathematics
1 answer:
julsineya [31]2 years ago
6 0

Answer:

Dr Notes Receivable $52,200

Cr Cash $52,200

Dec. 11

Dr Notes Receivable $1,800

Cr Cash $1,800

Dec. 16

Dr Notes Receivable $4,800

Cr Accounts Receivable $4,800

Dec. 31

Dr Interest Receivable $637

Cr Interest Revenue $637

Step-by-step explanation:

Preparation of the journal entries

Nov 1

Dr Notes Receivable $52,200

Cr Cash $52,200

Dec. 11

Dr Notes Receivable $1,800

Cr Cash $1,800

Dec. 16

Dr Notes Receivable $4,800

Cr Accounts Receivable $4,800

Dec. 31

Dr Interest Receivable $637

Cr Interest Revenue $637

($609+$8+$20)

Working:.

Interest Revenue

Note that 1 Nov to Dec 31st will give us 2 months

=$52,200 x 0.07 x 2/12 =$609

Note that Dec 11 to Dec 31st will give us 20 days

=$1,800 x 0.08 x 20/360 =$8

Note that Dec 16 to Dec 31st will give us 15 days

=$4,800 x 0.10 x 15/360=$20

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Step-by-step explanation:

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What is the z-score of a newborn who weighs 4,000 g?.
vagabundo [1.1K]

The z-score of the considered newborn having 4,000 g weight is \dfrac{4000 - \mu}{\sigma}

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

If we have

X \sim N(\mu, \sigma)

(X is following normal distribution with mean \mu and standard deviation  \sigma)

then it can be converted to standard normal distribution as

Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

P(Z \leq z) = P(Z < z) )

Also, know that if we look for Z = z in z tables, the p value we get is

P(Z \leq z) = \rm p \: value

For the considered case, the statement in the problem is missing the mean weight of the newborn and standard deviation of the data set of weights of newborn.

Thus, for them, we can consider variables in place of their actual values.

Let we have:

  • X = weights of newborns for some considered system (in grams)
  • \mu = mean weight of newborns (in grams)
  • \sigma = standard deviation of the data set of weights of newborns

Then, the z-score for X = 4000 is

z = \dfrac{x - \mu}{\sigma} = \dfrac{4000 - \mu}{\sigma}

Thus, the z-score of the considered newborn having 4,000 g weight is \dfrac{4000 - \mu}{\sigma}

Learn more about z-scores here:

brainly.com/question/13299273

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