Answer:
Active transport:
- Diffusion (one to far left)
- Facilitated diffusion (the one with glucose)
- Osmosis (the one with water)
Passive transport:
- Protein pump (one to far right)
Answer:
The thrust of the air propels the balloon in the opposite direction
Explanation:
Answer:
Differences between aerobic and anaerobic respiration is whether or not oxygen is present. . During aerobic respiration, carbon dioxide, water, and ATP are produced. During anaerobic respiration, lactic acid, ethanol, and ATP are create, aerobic os used when heart rate and breathing rate rise, anaerobic is used during the first 1-2 mins of exercise, occurs in the cytoplasm of cells, while aerobic occurs in the mitochondria of the cells, glycolysis occurs in both, both are respiration, and both create ATP
Explanation:
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
Answer:
If you were to ask me I would say that your answer is C
Explanation:
