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goblinko [34]
3 years ago
13

Yoko made 4 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 4 necklaces w

as $17.20 . If the beads cost a total of $9.60 , how much did each pendant cost?
Mathematics
2 answers:
aniked [119]3 years ago
7 0
$1.90 for each pendant

Can you please give me the brainliest answer? I am trying to get to the next rank, and my friend and I are competing :)
mestny [16]3 years ago
6 0
$1.90for each pendent
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Answer:

For tingle #1

We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.

C=180-(A+B)

C=180-(21.24+27.14)

C=131.62

We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.  

For triangle #2

In this one, we can find everything and there is one one value for each.

- We can find side c

Since we have a right triangle, we can find side c using the Pythagorean theorem

b^2=a^2+c^2

4^2=2^2+c^2

16=4+c^2

12=c^2

c=\sqrt{12}

c=2\sqrt{3}

- We can find angle C using the cosine trig identity

cos(C)=\frac{adjacent}{hypotenuse}

cos(C)=\frac{2}{4}

C=arccos(\frac{2}{4} )

C=60

- Now we can find angle A using the triangle sum theorem

A=180-(B+C)

A=180-(90+60)

A=30

For triangle #3

Again, we can find everything and there is one one value for each.

- We can find angle A using the triangle sum theorem

A=180-(B+C)

A=180-(90+34.88)

A=55.12

- We can find side a using the tangent trig identity

tan(C)=\frac{opposite-side}{adjacent-side}

tan(34.88)=\frac{7}{a}

a=\frac{7}{tan(34.88)}

a=10.04

- Now we can find side b using the Pythagorean theorem

b^2=a^2+c^2

b^2=10.04^2+7^2

b^2=149.8

b=\sqrt{149.8}

5 0
3 years ago
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