Answer:
2.24 s
Step-by-step explanation:
Given:
Δy = 80 ft
v₀ = 0 ft/s
a = 32 ft/s²
Find: t
Δy = v₀ t + ½ at²
80 ft = (0 ft/s) t + ½ (32 ft/s²) t²
t = 2.24 s
To start off, you need to take the cube root of both sides of the equation.
![\sqrt[3]{x} = \frac{ \sqrt[3]{27} }{ \sqrt[n]{64} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%7D%20%3D%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B27%7D%20%7D%7B%20%5Csqrt%5Bn%5D%7B64%7D%20%7D%20)
The cube root of 27 is 3, and the cube root of 64 is 4.
The answer would then be x=3/4
Salad and pbj: 24 students
Turkey sandwich and school lunch: 30 students
30
-
24
---------
6
Answer:
a=g
Step-by-step explanation:
If you are solving for 'a', then you just need to get 'a' separated on its own. To do this, you can multiply both sides of the equation by 'g'. Now you have "a=1g" which simplifies into "a=g"
Answer:
The correct option is:
cosθ = -3/5
Step-by-step explanation:
We have been given that:
cotθ = 3/4
such that the terminal side of θ lies in III quadrant.
Consider it a right angled triangle.
We know that:
cotθ = Base / Perpendicular
Which means Base has a magnitude of 3 and Perpendicular has the magnitude of 4.
As It lies in III quadrant, both x and y are negative.
So
Base = -3
Perpendicular = -4
Find the hypotenuse by using Pythagoras Theorem
H² = (-3)² + (-4)²
H = 5
We know that:
cosθ = Base / Hypotenuse
cosθ = -3/5
