Answer:
20) yes
21) -1
22) 1
23) -4
Step-by-step explanation:
Answer:
{x ∈ R: x<6}
Step-by-step explanation:
Given
- x is a real number
- x is less than 6
Required
Write the set using set builder notation
The very first thing to do is to list out the range of x, using inequalities;
x is less than 6 implies that -infiniti < x < 6
The next step is to translate this to set builder. This is done as follows
x ∈ R - > This means that x is a real number
x < 6 -> where x is less than 6.
Bringing these two together, it gives:
{x ∈ R: x<6}
Hence, the set of real numbers x less than 6 is equivalent to {x ∈ R: x<6} using set builder notation
3 9
_ * _
15 6
Compare diagonally to see if they the 2 numbers simplify.
Ex:
3 and 6 Simplify to 1 and 2 because they are both multiples of 3.
9 and 15 Simplify to 3 and 5 because they are both multiples of 3 as well.
Now our fractions are
1 3
_ * _
5 2
Now multiply across to get your final fraction/answer
3
_
10
Answer: 28.26
Step-by-step explanation:
What your looking for is called the annulus (or the difference of two concentric circles). You can find the annulus by subtracting the area of the inner circle from the area of the outer circle. Volume of a circle= πr²
You are given the diameter in these problems, so you need radius.
For the first circle (8 in one) :
8/2=4 r=4
A=3.14(4)²
A=50.24
For the second one (10 in one) :
10/2=5 r=5
A=3.14(5)²
A=78.5
To find the measure of the annulus, you subtract those numbers, getting 28.26
