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2 years ago

What is resultant force?

Physics

2 answers:

k0ka [10]2 years ago

5 0

Answer:

it is a force that result in anything to be done

Sergio039 [100]2 years ago

4 0

Answer:

In physics and engineering, a resultant force is the single force and associated torque obtained by combining a system of forces and torques acting on a rigid body. The defining feature of a resultant force, or resultant force-torque, is that it has the same effect on the rigid body as the original system of forces.

I hope it's helpful!

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A string has an abrupt change in linear density at its midpoint so that the speed of a pulse on the left side is 2/3 of that on

goldenfox [79]

Answer:

Explanation:

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When would a scientist accept the alternative

vredina [299]

Answer:

B.) if statistical results are significant

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If a scientist accepts the null hypothesis, then there is enough evidence to reject the null hypothesis.

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3 years ago

Find the direction of the sum of these two vectors: 12.0 m 45.0° 9.66 m. A m A,

Rina8888 [55]

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2 years ago

5.3 two 30 kg children in a 20 kg cart are stationary at the top of a hill. They start rolling down the 80 m tall hill and they

Makovka662 [10]

Answer:

60008.4 J

Explanation:

The mass of each kid = 30 kg

mass of the cart = 20 kg

The speed of the cart down the hill = 30 km/hr = 30 x 1000/3600 = 8.33 m/s

The height of the hill = 80 m

The potential energy of the boys at the top of the hill = mgh

where

m is the total mass of the kids and the cart = (30 x 2) + 20 = 80 kg

g is the acceleration due to gravity = 9.81 m/s^2

h is their height above the ground = 80 m (on the top of the hill)

substituting, we have

potential energy PE = 80 x 9.81 x 80 = 62784 J

At an instance at the bottom of the hill

their kinetic energy = $\frac{1}{2} mv^2$

where

v is their velocity = 8.33 m/s

m is their total mass = 80 kg

substituting, we have

kinetic energy KE = $\frac{1}{2}*80*8.33^2$ = 2775.6 J

Total work done on the cart is equal to the energy lost by the cart when it reached the bottom of the hill

work done by friction = PE - KE = 62784 - 2775.6 = 60008.4 J

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2 years ago