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adelina 88 [10]
3 years ago
13

How much power is required to light a lightbulb at 100V of voltage when the lightbulb has a resistance of 500 Ohms?

Physics
1 answer:
melisa1 [442]3 years ago
8 0

Answer:

20 Watt

Explanation:

Applying

P = V²/R................... Equation 1

Where V = Voltage, P = Power, R = resistance

From the question,

Given: V = 100V, R = 500 ohms

Substitute these values into equation 1

P = (100²)/500

P = 10000/500

P = 20 Watt.

Hence the power required to light the bulb is 20 W

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Explanation:

From the question we are told that

     The area is  A =  2.34*10^{-3} \ m^2

     The magnitude of charge placed on them is  q =  7.07 * 10^{-7} C

     The charge placed between the plate is q_1 = 6.62 *10^{-5} C

   

The electric field generated around the plate  is mathematically represented as

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        F =  q_1 * E

Substituting values  

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