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3 years ago

How much power is required to light a lightbulb at 100V of voltage when the lightbulb has a resistance of 500 Ohms?

Physics

1 answer:

melisa1 [442]3 years ago

8 0

Answer:

20 Watt

Explanation:

Applying

P = V²/R................... Equation 1

Where V = Voltage, P = Power, R = resistance

From the question,

Given: V = 100V, R = 500 ohms

Substitute these values into equation 1

P = (100²)/500

P = 10000/500

P = 20 Watt.

Hence the power required to light the bulb is 20 W

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Buoyant force is the upward pushing force whenever an object is trying to get immersed in fluid. So this is the force given by the fluid on the object which is trying to get immersed. The buoyant force is found to be directly proportional to the product of density of the object, volume of the object. And here the acceleration due to gravity will be acting as proportionality constant.

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